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PolarNik [594]
3 years ago
14

Based in bonding theory, explain why heat capacity increases when you consider metals, ceramics and polymers.

Engineering
1 answer:
Sonbull [250]3 years ago
4 0

Answer:

Metals are good conductors are heat. Many applications of ceramics, such as their use as insulating materials cause higher heating capacity. In the case of polymers, we have to distinguish between the heat capacity of liquid, rubbery and glassy polymers. The heat capacity increases with increasing temperature, therefore, a liquid or rubbery polymer can hold more energy than a solid polymer.  

Explanation:

Valence bond (VB) theory is a chemical bonding theory that explains the chemical bonding between two atoms. Like molecular orbital (MO) theory, it explains bonding using principles of quantum mechanics. According to valence bond theory, bonding is caused by the overlap of half-filled atomic orbitals. The two atoms share each other's unpaired electron to form a filled orbital to form a hybrid orbital and bond together. Sigma and pi bonds are part of valence bond theory.

Bonding, Structure and Properties

  1. The bonding and structure of substances determine their properties.
  2. Bonding is the way the atoms are held together.
  3. The structure is the way the atoms are arranged relative to each other.
  4. There are two major types of structure: giant and molecular.
  5. Giant structures go on indefinitely, whereas molecular structures are made up of groups of atoms.

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Please help this is due today!!!!!
White raven [17]

Answer:

1:c 2:False

Explanation:

7 0
3 years ago
Write a simple calculator program. Your program should ask for three things two whole numbers and an operator in the form of an
vekshin1

Answer:

The solution code is written in Java.

  1.        Scanner input = new Scanner(System.in);
  2.        System.out.print("Enter operator: ");
  3.        String operator = input.nextLine();
  4.        System.out.print("Enter first integer: ");
  5.        int num1 = input.nextInt();
  6.        System.out.print("Enter second integer: ");
  7.        int num2 = input.nextInt();
  8.        int result = 0;
  9.        switch(operator){
  10.            case "+":
  11.               result = num1 + num2;
  12.               break;
  13.            case "-":
  14.                result = num1 - num2;
  15.                break;
  16.            case "*":
  17.                result = num1 * num2;
  18.                break;
  19.            case "/":
  20.                result = num1 / num2;
  21.                break;
  22.            default:
  23.                System.out.println("Invalid operator");
  24.        }
  25.        System.out.println(result);

Explanation:

To ask for the user input for two whole numbers and an operator, we can use Java Scanner class object. Since the input operator is a string, we can use nextLine() method to get the operator string (Line 3). We use nextInt() method to get whole number input (Line 5 & 7).

Next we use the switch keyword and pass the operator into the switch structure to determine which case statement should be executed. For example,  if the input operator is "*" the statement  "<em>result = num1 * num2;</em> " will run and multiply <em>num1</em> with <em>num2. </em>

3 0
4 years ago
Water flows in a tube that has a diameter of D= 0.1 m. Determine the Reynolds number if the average velocity is 10 diameters per
Cloud [144]

Answer:

a) Re_{D} = 111896.745, b) Re_{D} = 1.119\times 10^{-7}

Explanation:

a) The Reynolds number for the water flowing in a circular tube is:

Re_{D} = \frac{\rho\cdot v\cdot D}{\mu}

Let assume that density and dynamic viscosity at 25 °C are 997\,\frac{kg}{m^{3}} 0.891\times 10^{-3}\,\frac{kg}{m\cdot s}, respectively. Then:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (1\,\frac{m}{s} )\cdot (0.1\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 111896.745

b) The result is:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (10^{-6}\,\frac{m}{s} )\cdot (10^{-7}\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 1.119\times 10^{-7}

6 0
4 years ago
John’s engineering team has just finished testing prototypes. What should be their next step in the design process?
VladimirAG [237]

Answer:

A.  implementation

Explanation:

5 0
3 years ago
The acceleration due to gravity at sea level is g=9.81 m/s^2. The radius of the earth is 6370 km. The universal gravitational co
solmaris [256]

Answer:

Mass of earth will be M=5.96\times 10^{24}kg

Explanation:

We have given acceleration due to gravity g=9.81m/sec^2

Radius of earth = 6370 km =6370\times 10^3m

Gravitational constant G=6.67\times 10^{-11}Nm^2/kg^2

We know that acceleration due to gravity is given by

g=\frac{GM}{R^2}, here G is gravitational constant, M is mass of earth and R is radius of earth

So 9.81=\frac{6.67\times 10^{-11}\times M}{(6370\times 10^3)^2}

M=5.96\times 10^{24}kg

So mass of earth will be M=5.96\times 10^{24}kg

3 0
3 years ago
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