<u>[Reflection]</u>
- This occurs when light bounces off a surface (reflection is when light bounces off of something, a medium, but doesn't go through.)
- Best with a smooth surface (it is easiest for light to bounce off when the surface is smooth)
- If not for this behavior, mirrors wouldn't work (mirrors use reflection, if they did not you would not be able to see your <em>reflection</em>)
<u>[Refraction]</u>
- Light moves from one medium to another (when light moves from one medium to another, it refracts)
- Lenses in your glasses to bend light waves (refraction is all about bending light waves, so this option falls under this category)
- Microscopes and telescopes take advantage of this behavior of light (again, refraction is bending light waves. When you bend a light wave, it can make it easier to see [larger, smaller, etc] so this option is refraction)
- Light wave changes speed (light does not change speed when being reflected because it is in the same medium and just bouncing, but it refraction is changes mediums so it will bend and change speed)
[Note]
- Some of these can be figured out by knowing the definitions. For example, refraction is defined as "change in direction ... of any wave as a result of its traveling at different speeds at different points along the wave front" (Oxf/ord Languages)
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer: Executive Order on Protecting American Monuments, Memorials, and Statues against our country are public monuments, memorials, and statues.
Explanation: learned it last week
Answer:
![\mu _j=\dfrac{1}{C_p}\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp](https://tex.z-dn.net/?f=%5Cmu%20_j%3D%5Cdfrac%7B1%7D%7BC_p%7D%5Cleft%20%5BT%5Cleft%28%5Cfrac%7B%5Cpartial%20v%7D%7B%5Cpartial%20T%7D%5Cright%29_p-v%5Cright%5Ddp)
Explanation:
Joule -Thompson effect
Throttling phenomenon is called Joule -Thompson effect.We know that throttling is a process in which pressure energy will convert in to thermal energy.
Generally in throttling exit pressure is low as compare to inlet pressure but exit temperature maybe more or less or maybe remains constant depending upon flow or fluid flow through passes.
Now lets take Steady flow process
Let
Pressure and temperature at inlet and
Pressure and temperature at exit
We know that Joule -Thompson coefficient given as
Now from T-ds equation
dh=Tds=vdp
So
![Tds=C_pdt-\left [T\left(\frac{\partial v}{\partial T}\right)_p\right]dp](https://tex.z-dn.net/?f=Tds%3DC_pdt-%5Cleft%20%5BT%5Cleft%28%5Cfrac%7B%5Cpartial%20v%7D%7B%5Cpartial%20T%7D%5Cright%29_p%5Cright%5Ddp)
⇒![dh=C_pdt-\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp](https://tex.z-dn.net/?f=dh%3DC_pdt-%5Cleft%20%5BT%5Cleft%28%5Cfrac%7B%5Cpartial%20v%7D%7B%5Cpartial%20T%7D%5Cright%29_p-v%5Cright%5Ddp)
So Joule -Thompson coefficient
This is Joule -Thompson coefficient for all gas (real or ideal gas)
We know that for Ideal gas Pv=mRT
So by putting the values in
For ideal gas.
Electricity<span> is </span>measured<span> in </span>units<span> of power called Watts</span>
Answer:
a = 4.96 m/s²
Explanation:
Given,
The mass of the box, m = 51 Kg
The magnitude of the applied force, Fₐ = 485 N
The friction force on the box, Fₓ = 232 N
The net force acting on the box is,
F = Fₐ - Fₓ
Substituting the given values in the above equation
F = 485 - 232
= 253 N
The acceleration of the crate is given by
a = F/m
= 253 / 51
= 4.96 m/s²
Hence, the acceleration of the crate is, a = 4.96 m/s²
