A tennis ball is hit by a large force so that it goes up into the air and then it comes back straight down because of gravity.
<h3>How object move upward and downward?</h3>
We know that objects move upward due to application of force on it while on the other hand, object comes to the ground because of the attraction of earth which we called gravity.
So we can conclude that a tennis ball is hit by a large force so that it goes up into the air and then it comes back straight down because of gravity.
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Answer:
dV/dt = 9 cubic inches per second
Explanation:
Let the height of the cylinder is h
Diameter of cylinder = height of the cylinder = h
Radius of cylinder, r = h/2
dh/dt = 3 inches /s
Volume of cylinder is given by

put r = h/2 so,

Differentiate both sides with respect to t.

Substitute the values, h = 2 inches, dh/dt = 3 inches / s

dV/dt = 9 cubic inches per second
Thus, the volume of cylinder increases by the rate of 9 cubic inches per second.
The net force on the box is:
50 + 30 - 65
= 15 Newtons
This can be used in conjunction with
F = ma
to calculate the acceleration of the box if its mass is known.
Answer:
The Electric flux will be 
Explanation:
Given
Strength of the Electric Field at a distance of 0.158 m from the point charge is

We know that the flux of the Electric Field can be calculated by using Gauss Law which is given by

Let consider a sphere of radius 0.158 m as Gaussian Surface at a distance of 0.158 m from the point charge and Let
be the flux of the Electric Field coming out\passing through it which is given by

It can be observed that same amount of flux which is passing through the Gaussian sphere of radius 0.158 is also passing through the Gaussian sphere of radius 0.142 m at a distance of 0.142 m from its centre.
Also it can be observed that the charge inside the two Gaussian Sphere mentioned have same value so the Flux of electric field through them will also be same.
So the electric flux through the surface of sphere that has given charge at its centre and that has radius 0.142 m is 
Answer:
μ =5.40 A-m²
Explanation:
The components of the net magnetic field are the magnetic field of the dipole and the magnetic field of Earth, then from the right triangle, the deflection angle is computed by
tan θ = Bdipole / Bearth ⇒ Bdipole = Bearth* tan θ
Bdipole = 2e-5 T*tan 70° = 5.49e-5 T
The magnetic field at the location of the compass due to the dipole has a magnitude
Bdipole = (μ₀/4π)(2μ/r³) ⇒ μ = Bdipole r³ / 2(μ₀/4π)
μ = (5.49e-5 T)(0.27m)³ / 2(1 × 10−7 T m² /(C m/s)) = 5.40 A-m²