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gayaneshka [121]
3 years ago
8

Explain why compressional waves are unable to move through vacuum

Chemistry
2 answers:
fgiga [73]3 years ago
7 0
A compression wave is transmitted by motion or particles. Sound is a compression wave that travels through gases, liquids and solids by moving atoms/molecules/particles which in turn bump into neighbouring atoms/molecules/particles.

In a vacuum there are no atoms, molecules or particles present to transmit the wave.
AnnyKZ [126]3 years ago
4 0
Can travel through<span> most media including a </span>vacuum. The electromagnetic ...Transverse waves<span> are </span>unable<span> to </span>pass through<span> liquids or gases.</span>
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Who's your celebrity crush and why?
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Answer:

Ian Somerhalder because he's JUST SO fine

Explanation:

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Amount of liquid measured in L or Lm
devlian [24]

The amount of liquid is measured in L. As the unit Lm is only used when measuring the mass liquid fraction.


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3 years ago
Use the data given below to construct a Born-Haber cycle to determine the heat of formation of KCl. Δ H°(kJ) K(s) → K(g) 89 K(g)
AURORKA [14]

Explanation:

The net equation will be as follows.

          K(s) + Cl_{2}(g) \rightarrow KCl(s)

So, we are required to find \Delta H_{formation} for this reaction.

Therefore, steps involved for the above process are as follows.

Step 1:  Convert K from solid state to gaseous state

          K(s) \rightarrow K(g),    \Delta H_{1} = 89 kJ

Step 2:  Ionization of gaseous K

           K(g) \rightarrow K^{+}(g) + e^{-},    H_{2} = 418 KJ

Step 3:  Dissociation of Cl_{2} gas into chlorine atom .

            \frac{1}{2} Cl_{2}(g) \rightarrow Cl(g),   \Delta H_{3} = \frac{244}{2} = 122 KJ

Step 4: Iozination of chlorine atom.

              Cl(g) + e^{-} \rightarro Cl^{-}(g),      H_{4} = -349 KJ

Step 5:  Add K^{+} ion and Cl^{-} ion formed above to get KCl .

              K^{+}(g) + Cl^{-}(g) \rightarrow KCl(s),   H_{5} = -717 KJ

Now, using Born-Haber cycle, value of enthalpy of the formation is calculated as follows.

      \Delta H_{f} = \DeltaH_{1} + \Delta H_{2} + \Delta H_{3} + \Delta H_{4} + \Delta H_{5}

                  = 89 + 418 + 122 - 349 - 717

                  = - 437 KJ/mol

Thus, we can conclude that the heat of formation of KCl is - 437 KJ/mol.

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3 years ago
Remove all the tape pieces from part A, and throw them in the trash. Next, follow these steps to compare pieces of sticky tape t
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The interaction which will occur when the non sticky tape pieces are turned towards each other is attraction.

<h3>What is Attraction?</h3>

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This however wears off after some time thereby making it the most appropriate choice.

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