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boyakko [2]
3 years ago
10

Harry Potter is chasing his nemesis Draco Malfoy during a quidditch match. Initially, Harry is 35m behind Draco, who has just sp

otted the Golden Snitch hovering 75m away at the edge of the playing field. Draco Flies at a constant speed of 40 m/s straight towards the Golden Snitch. If Harry is originally flying at 50 m/s, what acceleration does he need to reach the Snitch 175 m ahead of Draco? How fast will Harry be moving when he passes Draco?
Physics
1 answer:
Sophie [7]3 years ago
3 0

Answer:

the acceleration of harry is equal to 66.126 m/s²

Explanation:

given,

harry is 35 m behind Draco

speed of Draco = 40 m/s

original speed of harry = 50 m/s

acceleration = ?

time taken by the Draco

    t =\dfrac{r}{u} =\dfrac{75}{40}

     t = 1.875 s

distance covered by Harry

  d = 35 + 175 = 210 m

to calculate the acceleration of harry

s = u t+ \dfrac{1}{2}at^2

210 = 50\times 1.875+ \dfrac{1}{2}\times a\times 1.875^2

a × 3.516 × 0.5 = 116.25

a = 66.126 m/s²

hence, the acceleration of harry is equal to 66.126 m/s²

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The cost of energy delivered to residences by electrical transmission varies from $0.070/kWh to $0.258/kWh throughout the United
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Answer:

(a) $ 1.48

(b) $ 0.005

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Explanation:

(a)

First, we calculate the energy consumed, by using following formula:

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E = Energy Consumed = ?

P = Power Delivered = (40 W)(1 KW/1000 W) = 0.04 KW

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Therefore,  

E = (0.04 KW)(336 h) = 13.44 KWh

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Cost = (13.44 KWh)($ 0.11/KWh)

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(b)

First, we calculate the energy consumed, by using following formula:

E = Pt

where,

E = Energy Consumed = ?

P = Power Delivered = (970 W)(1 KW/1000 W) = 0.97 KW

t = Time Duration = (3 min)(1 h/60 min) = 0.05 h

Therefore,  

E = (0.97 KW)(0.05 h) = 0.0485 KWh

Now, we calculate cost, by following formula:

Cost = (E)(Unit Price)

Cost = (0.0485 KWh)($ 0.11/KWh)

<u>Cost = $ 0.005</u>

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(c)

First, we calculate the energy consumed, by using following formula:

E = Pt

where,

E = Energy Consumed = ?

P = Power Delivered = (5.203 x 10³ W)(1 KW/1000 W) = 5.203 KW

t = Time Duration = (40 min)(1 h/60 min) = 0.67 h

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E = (5.203 KW)(0.67 h) = 3.47 KWh

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Cost = (3.47 KWh)($ 0.11/KWh)

<u>Cost = $ 0.38</u>

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Water in a metal pot is heated over a campfire. Primarily, by wat means of energy transfer is thermal energy moved from the fire
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when water in a metal pot is heated over a campfire. Primarily, by means of convection energy transfer is thermal energy moved from the fire to the bottom of the pot

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Thermal energy can flow by different means such as conduction, convection, and radiation.

As given in the problem when water in a metal pot is heated over a campfire. The energy we receive around the campfire is mostly due to the effect of the radiation of the heat but the Primary means of energy transfer is thermal energy moved from the fire to the bottom of the pot because of the convection.

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A particular solvent with ΔS∘vap=112.9J/(K⋅mol)ΔSvap∘=112.9J/(K⋅mol) and ΔH∘vap=38.0kJ/molΔHvap∘=38.0kJ/mol is being considered
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Answer:

Explanation:

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