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lys-0071 [83]
2 years ago
14

I NEED THIS ASAP!!! A ball is thrown straight up with an initial velocity of 4.40 m/s. Assuming there is no air friction, what i

s the maximum height the ball will reach? 40pts pls
Physics
1 answer:
Lilit [14]2 years ago
5 0

Answer:

I think it is 80m/s

Explanation:

d = ½ g t2

  = ½ (10 m/s2) (4 s)2

  = (5 m/s2) (16 s2)

  = 80 ms

75% sure

Hope this helps!!!

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An all-electric car (not a hybrid) is designed to run from a bank of 12.0 V batteries with total energy storage of 2.30 ✕ 107 J.
AnnyKZ [126]

Answer:

a) I=733.33\ A

b) d=52272.7273\ m

c) d'=51948.0519\ m

Explanation:

Given:

  • voltage of the battery, V=12\ V
  • energy storage capacity of the battery, E=2.3\times 10^7\ J
  • speed of the car, v=20\ m.s^{-1}

a)

power drawn by the car, P=8.8\ kW

<u>Now the Current delivered to the motor:</u>

we the relation between the power and electrical current,

P=V.I

8800=12\times I

I=733.33\ A

b)

<u>Distance travelled before battery is out of juice:</u>

we first find the time before the battery runs out,

t=\frac{E}{P}

t=\frac{2.3\times 10^7}{8800}

t=2613.636\ s

Now the distance:

d=v.t

d=20\times 2613.636

d=52272.7273\ m

c)

When the head light of 55 W power is kept on while moving then the power   consumption of the car is:

P'=P+55

P'=8800+55

P'=8855\ W

<u>Now the time of operation of the car:</u>

t'=\frac{E}{P'}

t'=\frac{2.3\times 10^7}{8855}

t'=2597.4026\ s

<u>Now the distance travelled:</u>

d'=v.t'

d'=20\times 2597.4025

d'=51948.0519\ m

5 0
2 years ago
An aluminum clock pendulum having a period of 1.00 s keeps perfect time at 20.0°C.
amm1812

Answer:

a) T ’= 0.999 s ,  b)  t = 3596.4 s

Explanation:

The angular velocity of a simple pendulum is

        w = √g / L

The angular velocity, frequency and period are related

        w = 2π f = 2π / T

        2π / T = √ g / L

        T = 2π √ L / g

        L = T² g / 4π²

        L = 1² 9.8 / 4π²

        L = 0.248 m

To know the effect of the temperature change let's use the thermal expansion ratios

       ΔL = α L ΔT

       ΔL = 24 10⁻⁶ 0.248 (-4 - 20)

       ΔL = 142.8 10⁻⁶ m

       Lf - L = -142. 8 10⁻⁶

       Lf = 142.8 10⁻⁶ + 0.248

       Lf = 0.2479 m

Let's calculate new period

      T ’= 2π √ L / g

      T ’= 2π √ (0.2479 / 9.8)

      T ’= 0.999 s

We can see that the value of the period is reduced so that the clock is delayed

b) change of time in 1 hour

When the clock is at 20 ° C in one hour it performs 3600 oscillations, for the new period the time of this number of oscillations is

       t = 3600 0.999

       t = 3596.4 s

Therefore the clock is delayed almost 4 s

6 0
3 years ago
A 95 kg clock initially at rest on a horizontal floor
Nataly [62]

Answer:

You are given that the mass of the clock M is 95 kg.

This is true whether the clock is in motion or not.

Fs is the frictional force required to keep the clock from moving.

Thus Fk = uk W = uk M g      the force required to move clock at constant speed.     (the kinetic frictional force)

uk = 560 N / 931 N = .644   since the weight of the clock is 931 N  (95 * 9.8)

us  is the frictional force requited to start the clock moving

us = static frictional force = 650 / 931 -= .698

4 0
3 years ago
Write two examples of chemical properties and explain what they are
Gre4nikov [31]
Chemical Properties are properties of a substance that are seen during a chemical reaction. In other words, chemical properties cannot be found by looking/touching the substance. Those are its physical properties.

Examples

Flammability
toxicity
solubility
Acidity
Electronegativity
6 0
3 years ago
Consider a physical situation in which a particle moves from point A to point B. This process is described from two coordinate s
Fudgin [204]

Coordinates, displacement

8 0
3 years ago
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