Answer:
23.49m
Explanation:
Distance = velocity x time
8.7 x 2.7 = 23.49m
Answer:
V = a * t = 9.8 m/s^2 * 2.3 s = 22.5 m/s velocity after 2.3 s
S = 1/2 g t^2 since initial speed is zero
S = 1/2 * 9.8 m/s^2 * 5.29 s^2 = 25.9 m
Answer:
The frequency of the oscillation is 2.45 Hz.
Explanation:
Given;
mass of the spring, m = 0.5 kg
total mechanical energy of the spring, E = 12 J
Determine the spring constant, k as follows;
E = ¹/₂kA²
kA² = 2E
k = (2E) / (A²)
k = (2 x 12) / (0.45²)
k = 118.519 N/m
Determine the angular frequency, ω;

Determine the frequency of the oscillation;
ω = 2πf
f = (ω) / (2π)
f = (15.396) / (2π)
f = 2.45 Hz
Therefore, the frequency of the oscillation is 2.45 Hz.
Answer:
5.31143691523 m/s²
Explanation:
m = Mass = 280 g
x = Displacement of spring = 21.7 cm
Time period

Angular velocity is given by


From Hooke's law

The acceleration due to gravity on the planet is 5.31143691523 m/s²
Yes, I have been able to satisfy my curiosity.
Answer:
Flow rate of air is given as 83.33 cubic feet per minute
Explanation:
As we know that total volume of the air flow is given as

also we know that total time is

now we have flow rate given as


