<span>During neutralization reaction
Milliequivalent of acid=milliequivalent of base.
Milliequivalent of HCl=0.100*12*1
Milliequivalent of NaOH=M*10*1
So 0.100*12*1=M*10*1
Solve for M.</span>
It would be 20 give me bravest
It would be 4.6cgL not sure tho because I didint do that good in this
The correct answer is Bromine
Hope this helped:)
Answer:
B. Four moles of water were produced from this reaction.
Explanation:
I took the test and got it correct
