Answer:
skskkdkdkfkgkgkgkkgkgkgigooigigi lol
Explanation:
Oof
Efficiency is the minimum use of energy to accomplish the task. The wasted energy will be 375 J when 750 J of energy is given.
<h3>What is wasted energy?</h3>
Wasted energy is energy that is not useful when the transformation in the system occurs.
Total energy = 750 J
The efficiency of the system = 50 %
Output work (OW) is calculated as:
Efficiency = output work ÷ input work × 100%
750 × 50 = 100 OW
OW = 375 J
Wasted energy = Total energy - output work
= 750 - 375
= 375 J
Therefore, the machine is 50 % inefficient and has wasted energy of 375 J.
Learn more about wasted energy here:
brainly.com/question/16177264
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Answer and Explanation:
The crack formation growth that takes place in an environment corrosive.
Stress corrosion cracks can be defined as the spontaneous failures of the metal alloy as a result of the combined action of corrosion and high tensile stress.
Some of the characteristic features of stress corrosion cracks are:
- These occur at high temperatures.
- Occurrence of failures in metals mechanically.
- Occurrence of sudden and unexpected failures under tensile stress.
- The rate of work hardening of the metal alloy is high.
- Time
- An environment that is specific for stress corrosion cracking.
Answer:
Q = 62 ( since we are instructed not to include the units in the answer)
Explanation:
Given that:
Q = ???
Now the gas expands at constant pressure until its volume doubles
i.e if 
Using Charles Law; since pressure is constant
mass of He =number of moles of He × molecular weight of He
mass of He = 3 kg × 4
mass of He = 12 kg
mass of Ar =number of moles of Ar × molecular weight of Ar
mass of He = 7 kg × 40
mass of He = 280 kg
Now; the amount of Heat Q transferred = 
From gas table
∴ Q = 
Q = 
Q = 62 MJ
Q = 62 ( since we are instructed not to include the units in the answer)
Answer:
Detailed solution is given in the attached diagram
