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Inessa [10]
2 years ago
5

How many atoms of Hydrogen in the products of the following equation?

Chemistry
1 answer:
love history [14]2 years ago
7 0

Answer:

2 atoms of H in the products side

Explanation:

3NO₂ + H₂O → NO + 2HNO₃

In product side: 3 N (1 from NO and 6 from nitric acid), 7 O (6 from nitric acid + 1 from NO), 2 H

In reactant side: 3 N, 7 O (6 from the dioxide + 1 from water) and 2 H

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Determine the percentage of carbon and hydrogen in ethane C2H6 if the molecular weight is 30.
Naddika [18.5K]

Answer:

Percentage of carbon:

{ \tt{ =  \frac{24}{30}  \times 100\%}} \\  = 80\%

Percentage of hydrogen:

{ \tt{ =  \frac{6}{30}  \times 100\%} } \\  = 20\%

8 0
3 years ago
Liquid hexane
maks197457 [2]

<u>Answer:</u> The mass of H_2O produced is 2.52 g

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

  • <u>For hexane:</u>

Given mass of hexane = 1.72 g

Molar mass of hexane = 86.18 g/mol

Putting values in equation 1, we get:

\text{Moles of hexane}=\frac{1.72g}{86.18g/mol}=0.020mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 8.0 g

Molar mass of oxygen gas= 32 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{8.0g}{32g/mol}=0.25mol

The chemical equation for the combustion of hexane follows:

2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O

By stoichiometry of the reaction:

If 2 moles of hexane reacts with 19 moles of oxygen gas

So, 0.020 moles of hexane will react with = \frac{19}{2}\times 0.020=0.19mol of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, hexane is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of hexane produces 14 moles of H_2O

So, 0.020 moles of hexane will produce = \frac{14}{2}\times 0.020=0.14mol of H_2O

We know, molar mass of H_2O = 18 g/mol

Putting values in above equation, we get:

\text{Mass of }H_2O=(0.14mol\times 18g/mol)=2.52g

Hence, the mass of H_2O produced is 2.52 g

4 0
3 years ago
The measure of the amount of dissolved salt in a liquid sample is called
Ann [662]

The answer is salinity, salinity is the saltiness or dissolved inorganic salt content of a body of water.

7 0
3 years ago
Find the no. of atoms present in 40g of nitrogen gas at STP?
nika2105 [10]

Answer:

8.60 * 10^{23} atoms N2

Explanation:

We want to convert grams to moles and then moles to atoms.

First, we convert grams of nitrogen gas (which is N2) to moles. To do so, we need the molar mass of N2, which is just 14.01 * 2 = 28.02 g.

40 g N2 * \frac{1 mol N2}{28.02 g N2} = 1.43 mol N2

Now, we need to convert moles to atoms by using Avogadro's number, which is 6.022*10^{23}:

1.43 mol N2 * \frac{6.022*10^{23} atoms N2 }{1 mol N2} = 8.60 * 10^{23} atoms N2

Thus, the answer is 8.60 * 10^{23} atoms N2.

6 0
3 years ago
Explain how the periodic table can help in writing electron configurations
Hoochie [10]
Period : the no. of electron shells
group: the last no. of electron configuration
4 0
3 years ago
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