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Inessa [10]
3 years ago
5

How many atoms of Hydrogen in the products of the following equation?

Chemistry
1 answer:
love history [14]3 years ago
7 0

Answer:

2 atoms of H in the products side

Explanation:

3NO₂ + H₂O → NO + 2HNO₃

In product side: 3 N (1 from NO and 6 from nitric acid), 7 O (6 from nitric acid + 1 from NO), 2 H

In reactant side: 3 N, 7 O (6 from the dioxide + 1 from water) and 2 H

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Gasoline has a density of 0.749 g/mL. How many pounds does 19.2 gallons of gasoline weigh? Use significant figures. Do not enter
Yanka [14]
In this question, you are given the gasoline density (0.749g/ml) and volume of the gasoline (19.2 gallons). You are asked the mass of the gasoline in pounds. Then you need to change the grams into pounds and the ml into gallons. The calculation would be:

mass of gasoline= density * volume
mass of gasoline=  0.749g/ml * (1 pound/453.592grams) * 3785.41ml/gallon * 19.2 gallon= 120 pounds

7 0
3 years ago
What is polyethylene??defination​
rewona [7]

Answer:

a tough, light, flexible synthetic resin made by polymerizing ethylene, chiefly used for plastic bags, food containers, and other packaging.

Explanation:

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3 years ago
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A sulfuric acid solution containing 571.3 g of h2so4 per liter of aqueous solution has a density of 1.329 g/cm3. Part a calculat
loris [4]

Mass percentage of a solution is the amount of solute present in 100 g of the solution.

Given data:

Mass of solute H2SO4 = 571.3 g

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Density of solution = 1.329 g/cm3 = 1.329 g/ml

Calculations:

Mass of the given volume of solution = 1.329 g * 1000 ml/1 ml = 1329 g

Therefore we have:

571.3 g of H2SO4 in 1329 g of the solution

Hence, the amount of H2SO4 in 100 g of solution= 571.3 *100/1329 = 42.987

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3 0
3 years ago
An unknown compound has a percent composition of 52.10% potassium, 15.8% carbon, and 32.1% oxygen. The molar mass of the compoun
lianna [129]
To determine the empirical formula and the molecular formula of the compound, we assume a basis of the compound of 100 g. We do as follows:

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K    52.10     52.10/39.10 = 1.33         1.33/1.32 ≈ 1
C    15.8       15.8/12         = 1.32         1.32/1.32 ≈ 1
O     32.1      32.1 / 16       =  2.01        2.01/1.32 ≈ 1.5

The empirical formula would most likely be KCO.
The molecular formula would be K2C2O3.
4 0
3 years ago
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Help pls ASAP thank you!!
BigorU [14]

Answer:

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