What is the momentum of a 73 person running with a speed of 2 m/s
1 answer:
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They are related as
- In a uniform circular motion, the magnitude of the speed does not change during the travel and only the instantaneous direction changes.
- This speed is always directed along the tangent to the circle at a given point. (refer to the figure attached)
- For any circular motion, the must-have acceleration is the centripetal acceleration that is directed towards the centre of the circular locus (if the motion has a tangential acceleration, it has a tangential acceleration additionally).
- Therefore, both the directions of the tangential speed and the centripetal acceleration are orthogonal to each other (perpendicular: one is 90 degrees apart from the other).
- In mathematics, 2 vectors (
,
) that are perpendicular to each other have a quality that their dot product (
) equal to zero vector (
) which is written as
.
- This quality can be considered when dealing with the velocity vector and the acceleration vector in a manner
.
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Answer:
Explanation:
We shall take the help of vector form of displacement . Taking east as i and north as j
4.0m N = 4 j
7.5 m E = 7.5 i
6.8 m S = - 6.8 j
3.7 m E, = 3.7 i
3.6 m S = - 3.6 j
5.3 m W = - 5.3 i
3.7 m N, = 3.7 j
5.6 m W = - 5.6 i
4.4 m S = - 4.4 j
4.9 m W = - 4.9 i
Total displacement = 4j +7.5 i -6.8j+3.7i-3.6j-5.3i+3.7j-5.6i-4.4j-4.9i
= -4.6 i -7.1 j
magnitude of displacement =
= 8.46 m
Direction
Tanθ = 7.1/ 4.6
θ = 57⁰ south of west .
distance walked = 4+7.5 +6.8+3.7+3.6+5.3+3.7+5.6+4.4+4.9
= 49.5 m