Heat transfer in a closed system is the addition of changes in internal energy and the total amount of work done by it. The final energy of the system is 35.5kJ.
<h3>What is heat transfer? </h3>
Heat transfer is the transfer of heat energy due to temperature differences.
The paddle-wheel paintings are quantities of workdone, 500 N.m or 0.5kJ.
The preliminary (initial) power of the device is 10 kJ.
Total warmness transferred in the course of the method is 30 kJ
Total warmness misplaced in the course of the method to the encompassing air is 5 kJ.
The energy of the system is given as:
The energy of the system = Energy in - Energy out
The energy of the system = Initial energy + Energy transferred + Work done - Energy lost
Energy of the system = 10 + 30 + 0.5 - 5 kJ
Energy of the system = 35.5 kJ
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The voltage in the resistor is 63 V
Explanation:
We can solve the problem by applying Ohm's law, which states the relationship between voltage, current and resistance in a resistor:
where
V is the voltage
R is the resistance
I is the current
For the resistor in this problem, we have:
I = 0.42 A is the current
is the resistance
Substituting into the equation, we find the voltage needed:
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Answer:
2.9 cm
Explanation:
Assuming that the rear wheel has a radius of 0.330 m
Given that
r(a) = 12 cm -> 0.12 m
w(a) = 0.6 rev/s -> 3.77 rad/s
v = 5 m/s
r(w) = 0.330 m
The speed on any point on the rim at the sprocket in the front is
v(a) = w(a).r(a) = 3.77 * 0.12 = 0.4524 m/s
Also,
v(a) = speed at any point on the chain
v(b) = speed at any point on the rim of the rear sprocket
v(a) = v(b)
where v(b) = w(b).r(b)
Recall that the speed at any point on the rear wheel is v, where
v = w(b).r(w)
5 = w(b) * 0.330
w(b) = 5/0.330
w(b) = 15.15 rad/s
On substituting this in the equation, we have
v(b) = w(b).r(b).
Remember also, that v(a) = v(b), so
0.4524 = 15.15 * r(b)
r(b) = 0.4524 / 15.15
r(b) = 0.029 m -> 2.9 cm
Therefore, the radius of the rear sprocket needed is 2.9 cm
Answer:
Explanation:
Assuming there is no waste of energy:
