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Anton [14]
3 years ago
11

In a second trial of this experiment, the molarity of koh(aq) was determined to be 0.95 m. the actual molarity was 0.83 m. what

is the percent error in the second trial?
Chemistry
1 answer:
Cloud [144]3 years ago
5 0
 The % error in the second trial  is calculated as follows

% error = actual molarity/  theoretical molarity  x100


= 0.83/0.95 x100 = 87.4% error of second trial
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