In a second trial of this experiment, the molarity of koh(aq) was determined to be 0.95 m. the actual molarity was 0.83 m. what

Question

Anton [14]

3 years ago

11

In a second trial of this experiment, the molarity of koh(aq) was determined to be 0.95 m. the actual molarity was 0.83 m. what

is the percent error in the second trial?

Chemistry

1 answer:

Cloud [144] · Answer 1 · 2022-02-03T04:24:41+03:00

Cloud [144]3 years ago

5 0

The % error in the second trial is calculated as follows

% error = actual molarity/ theoretical molarity x100

= 0.83/0.95 x100 = 87.4% error of second trial