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gtnhenbr [62]
3 years ago
5

A student studies photosynthesis and cellular respiration in plants. Which of the following reactions would produce 12 grams (g)

of glucose and oxygen?
when a total of 12g of carbon dioxide and water react in photosynthesis


when a total of 24g of carbon dioxide and water react in photosynthesis


when a total of 12g of carbon dioxide and water react in cellular respiration


when a total of 24g of carbon dioxide and water react in cellular respiration
Chemistry
1 answer:
spayn [35]3 years ago
6 0

Answer:

The answer is A

Explanation:

Because I used the elimination rule none of the other ones could be an answer.

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nikdorinn [45]

Answer:

Option ( 1 )

Explanation:

This atom has a cub close pack structure, and therefore - the number of edge center present in X atoms =  4,

Number of unit cells present in X atoms = 6

____________________________________________________

Now the 6th coordination number of X atom = 6 * 4 = 24,

So respectively, the 3rd coordination number of X = 8 -

And thus the ratio between the 6th coordination number and the 3rd coordination number = 24 / 8 = 3,

Option ( 1 )

<u><em>Hope that helps!</em></u>

5 0
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Answer:

The correct answer is :

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6 0
3 years ago
What are the variables in Gay-Lussac’s law?
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6 0
3 years ago
In the chemical reaction in which sucrose is heated and decomposes to form carbon dioxide and water, which of the following is a
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You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1
jeka57 [31]

Answer:

\boxed{\text{36 mL}}

Explanation:

1. Write the balanced chemical equation.

\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O

2. Calculate the moles of HCOOH

\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}

3. Calculate the moles of NaOH.

\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}

4. Calculate the volume of NaOH

c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}

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