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gtnhenbr [62]
3 years ago
5

A student studies photosynthesis and cellular respiration in plants. Which of the following reactions would produce 12 grams (g)

of glucose and oxygen?
when a total of 12g of carbon dioxide and water react in photosynthesis


when a total of 24g of carbon dioxide and water react in photosynthesis


when a total of 12g of carbon dioxide and water react in cellular respiration


when a total of 24g of carbon dioxide and water react in cellular respiration
Chemistry
1 answer:
spayn [35]3 years ago
6 0

Answer:

The answer is A

Explanation:

Because I used the elimination rule none of the other ones could be an answer.

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Enter your answer in the provided box. The atomic masses of 63Cu (69.17 percent) and 65Cu (30.83 percent) are 62.94 and 64.93 am
dybincka [34]

<u>Answer:</u> The average atomic mass of copper is 63.55 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

  • <u>For _{29}^{63}\textrm{Cu} isotope:</u>

Mass of _{29}^{63}\textrm{Cu} isotope = 62.94 amu

Percentage abundance of _{29}^{63}\textrm{Cu} = 69.17 %

Fractional abundance of _{29}^{63}\textrm{Cu} isotope = 0.6917

  • <u>For _{29}^{65}\textrm{Cu} isotope:</u>

Mass of _{29}^{65}\textrm{Cu} isotope = 64.93 amu

Percentage abundance of _{29}^{65}\textrm{Cu} = 30.83 %

Fractional abundance of _{29}^{65}\textrm{Cu} isotope = 0.3083

Putting values in equation 1, we get:

\text{Average atomic mass of Copper}=[(62.94\times 0.6917)+(64.93\times 0.3083)]\\\\\text{Average atomic mass of copper}=63.55amu

Hence, the average atomic mass of copper is 63.55 amu.

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3 years ago
7) Calculate the number of moles of Chlorine gas if 50.0L of the gas is at 0.50atm of pressure at 400K.
Ostrovityanka [42]

Answer:

so i never did this befor so i am sorry hope you get the answer

Explanation:

7 0
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Answer:

b) velocity.

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Using the reaction below: 2 CO2(g) + 2 H2O(l) → C2H4(g) + 3 O2(g) ΔHrxn= +1411.1 kJ What would be the heat of reaction for this
maw [93]

Answer:  d) -705.55 kJ

Explanation:

Heat of reaction is the change of enthalpy during a chemical reaction with all substances in their standard states.

2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g) \Delta H=+1411.1kJ

Reversing the reaction, changes the sign of \Delta H

C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)

\Delta H=-1411.1kJ

On multiplying the reaction by \frac{1}{2} , enthalpy gets half:

0.5C_2H_4(g)+1.5O_2(g)\rightarrow CO_2(g)+H_2O(l)\Delta H=\frac{1}{2}\times -1411.1kJ=-705.55kJ/mol

Thus the enthalpy change for the given reaction is -705.55kJ

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