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AleksAgata [21]
3 years ago
8

Martin slowly pours an unknown liquid into a container that originally had some water in it. He is measuring the temperature in

the container as he does this.
The temperature in the container rises very fast.

What kind of change is likely to be happening in the container?

A. A physical change.

B. A chemical change.

C. Neither a chemical nor a physical change, only a temperature change.

D. No evidence of any type of change.
Chemistry
2 answers:
Evgen [1.6K]3 years ago
8 0
B. a chemical change
motikmotik3 years ago
7 0

Answer:

B. A chemical change.

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How does the amount of salt dissolve in water affect the density of water
ad-work [718]

Answer:

Adding salt to the water increases the density of the solution because the salt increases the mass without changing the volume very much. When you add table salt (sodium chloride, NaCl) to water, the salt dissolves into ions, Na+ and Cl-. The volume increases by a small factor, but the mass increases by a bigger factor.

Explanation:

3 0
3 years ago
Consider these changes.
Ede4ka [16]

Answer:

(a) The system does work on the surroundings.

(b) The surroundings do work on the system.

(c) The system does work on the surroundings.

(d) No work is done.

Explanation:

The work (W) done in a chemical reaction can be calculated using the following expression:

W = -R.T.Δn(g)

where,

R is the ideal gas constant

T is the absolute temperature

Δn(g) is the difference between the gaseous moles of products and the gaseous moles of reactants

R and T are always positive.

  • If Δn(g) > 0, W < 0, which means that the system does work on the surroundings.
  • If Δn(g) < 0, W > 0, which means that the surroundings do work on the system.
  • If Δn(g) = 0, W = 0, which means that no work is done.

<em>(a) Hg(l) ⇒ Hg(g)</em>

Δn(g) = 1 - 0 = 1. W < 0. The system does work on the surroundings.

<em>(b) 3 O₂(g) ⇒ 2 O₃(g) </em>

Δn(g) = 2 - 3 = -1. W > 0. The surroundings do work on the system.

<em>(c) CuSO₄.5H₂O(s) ⇒ CuSO₄(s) + 5H₅O(g) </em>

Δn(g) = 5 - 0 = 5. W < 0. The system does work on the surroundings.

<em>(d) H₂(g) + F₂(g) ⇒ 2 HF(g)</em>

Δn(g) = 2 - 2 = 0. W = 0. No work is done.

3 0
3 years ago
which factor would increase the carrying capacity for a white-tailed deer in an eastern temperate forest ecosystem
saveliy_v [14]
This is a guess, but I think it could be the lack of limiting factors.
4 0
3 years ago
Read 2 more answers
I need the answer today!
olchik [2.2K]

_____________________________________________

<h2 /><h2 /><h2><u>Solution </u><u>3</u><u> Is The Most Concentrated</u></h2>

<h3>S1:</h3>

M = m/v

= 100ml ÷ 2 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

<h3>S2:</h3>

M = m/v

= 200ml ÷ 5 spoons × 100%

= - 4,000 μg/ppb³

= <u>40% Diluted</u>

<h3>S3:</h3>

M = m/v

= 300ml ÷ 6 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

<h3>S4: </h3>

M = m/v

= 600ml ÷ 8 spoons × 100%

= - 75,000 μg/ppb³

= <u>75% Diluted</u>

_____________________________________________

8 0
3 years ago
Write the name for each of the following chemical formulas. <br> d. P3N5 (for doping semiconductors)
rewona [7]

Answer:

Triphorphorus Pentanitride

Explanation:

since there are three phosphorus use the prefix tri-, since there are five nitrogen use the prefix penta. tri=3, penta=5. then add a suffix -ide to the end of nitrogen. that will give you triphosphorus pentanitride.

3 0
2 years ago
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