On the basis of the given unbalanced equation, that is:
HBr (aq) + 2NaOH (aq) → 2NaBr (s) + H2O (l)
On the right side of the equation, there are 2 atoms of sodium (Na), 2 atoms of bromine (Br), 2 atoms of hydrogen (H), and 1 atom of oxygen (O₂).
After balancing the equation correctly we get:
HBr (aq) + NaOH (aq) → NaBr (s) + H2O (l)
On the right side, one atom of Na, 1 atom of Br, 1 atom of H and one atom of O₂.
The answer is group 1A.
In the ionic compound formula X₂SO₄, SO₄ has a -2 charge. Hence to balance this -2 charge of SO₄, X must have a +1 charge.
Group 1A elements form X⁺ type of ions because they are metals. So, they have the tendency to lose electrons.
Hence, X must belong to the 1A group.
Ionic Compounds-
- Ionic compounds are formed by the electrostatic attraction between the anions and the cations.
- Cations are positively charged ions that are formed due to the loss of electrons.
- And the anions are negatively charged ions that are formed due to the gain of electrons.
- Due to this, they have opposite charges and form bonds known as Ionic Bond.
To learn more about Ionic compounds, visit: brainly.com/question/9167977
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