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Sedbober [7]
3 years ago
15

Can someone help me on balancing chemical equations??

Chemistry
1 answer:
max2010maxim [7]3 years ago
3 0
What is the equation?
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The specific heat of gold is 0.031 calories/gram°C and the specific heat of silver is 0.057 calories/gram°C. If equal amounts of
Vikki [24]
I think the substance that will heat up faster would be the silver metal since it has a higher heat capacity. Heat capacity is the amount of heat needed to raise the temperature of the system into one degree. Heat capacity and heat energy is directly related so higher value of heat capacity would lead to higher heat energy.
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3 years ago
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In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol).Calculate the number of moles of chlo
sveticcg [70]
1 mole = 70.9
X mole = 140
X=1.9746 moles
X= 1.98 when rounded to 3 significant figures.
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3 years ago
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How many grams is 5.8 moles of hydrochloric acid (HCI)?<br> Answer to the nearest 0.01 g.
Anvisha [2.4K]

Answer:

211.47 grams

Explanation:

We need to set up a dimensional analysis to solve this problem by converting from moles to grams.

First, find the molar mass of HCl. Since the molar mass of H (hydrogen) is 1.01 g/mol and the molar mass of Cl (chlorine) is 35.45 g/mol, then the molar mass of HCl is:

1.01 + 35.45 = 36.46 g/mol

We have 5.8 moles of HCl, so multiply by its molar mass:

(5.8 mol) * (36.46 g/mol) = 211.468 ≈ 211.47 g

The answer is thus 211.47 grams.

<em>~ an aesthetics over</em>

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If 5 L of butane is reacted what volume of carbon dioxide is produced ILL GIVE BRAINLIEST
Len [333]

Answer: First, here is the balanced reaction:  2C4H10  +  13O2  ===>  8CO2  +  10H2O.

This says for every mole of butane burned 4 moles of CO2 are produced, in other words a 2:1 ratio.

Next, let's determine how many moles of butane are burned.  This is obtained by

5.50 g / 58.1 g/mole  =  0.0947 moles butane.  As CO2 is produced in a 2:1 ratio, the # moles of CO2 produced is 2 x 0.0947  =  0.1894 moles CO2.

Now we need to figure out the volume.  This depends on the temperature and pressure of the CO2 which is not given, so we will assume standard conditions:  273 K and 1 atmosphere.

We now use the ideal gas law PV = nRT, or V =nRT/P, where n is the # of moles of CO2, T the absolute temperature, R the gas constant (0.082 L-atm/mole degree), and P the pressure in atmospheres ( 1 atm).

V = 0.1894 x 0.082 x 273.0 / 1  =  4.24 Liters.

Explanation:

8 0
3 years ago
If 50g of calcium carbonate is heated, what mass of calcium oxide is formed
tresset_1 [31]

Answer:

22 g of CO2 are obtained from decomposition of 50 g of CaCO3

Explanation:

5 0
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