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Murljashka [212]
3 years ago
13

Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the

third bright fringe occurs at ± 3.10 cm on either side of the central bright fringe. How far apart are the two slits?
Physics
1 answer:
IgorC [24]3 years ago
7 0

Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

Frequency f= 6.37\times10^{14}\ Hz

Distance of the screen l = 88.0 cm

Position of the third order y =3.10 cm

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{c}{f}

where, c = speed of light

f = frequency

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}

\lambda=471\ nm

We need to calculate the distance between the two slits

m\times \lambda=d\sin\theta

d =\dfrac{m\times\lambda}{\sin\theta}

Where, m = number of fringe

d = distance between the two slits

Here, \sin\theta =\dfrac{y}{l}

Put the value into the formula

d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}

d=40.11\times10^{-6}\ m

d = 40.11\ \mu m

Hence, The distance between the two slits is 40.11 μm.

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notka56 [123]

Answer:

Explanation:

P = F/A

F = 1200 N

A = 2 m^2

P = 1200N/2 m^2

P = 600 N / m^2

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What will be the length of a half wavelength dipole antenna operating at 10GHz?
iVinArrow [24]

Given :

Frequency , \nu = 10\ GHz .

To Find :

The length of a half wavelength dipole .

Solution :

Now , wavelength is given by :

\lambda=\dfrac{c}{\nu}\\\\\lambda=\dfrac{3\times 10^8\ m/s}{10\ GHz}\\\\\lambda=\dfrac{3\times 10^8}{10\times 10^9}\ m\\\\\lambda=0.03\ m\\\\\lambda=3 \ cm

Now , half length is given by :

L=\dfrac{\lambda}{2}\\\\L=\dfrac{3}{2}\ cm\\\\L=1.5 \ cm

Therefore , length of a half wavelength dipole is 1.5 cm .

Hence , this is the required solution .

4 0
3 years ago
Ludwig Boltzmann performed a simple, but powerful experiment to gather evidence concerning the velocity distribution of a sample
sp2606 [1]

Answer:

Ludwig Boltzmann was an Austrian Physicist and he performed a simple but powerful experiment to gather evidence concerning the velocity distribution of a sample of gas particles.

His experiment revealed that the way Gases are distributed in its normal form across a range of temperature is dependent on the molar mass amen temperature of the gas. Gases with high temperature move faster due to the high number of colliding particles when compared to those with low temperature. Gases with lower molar mass move faster than those with higher molar mass.

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Use the velocity vs time graph to analyze the motion of the object.
arsen [322]

Explanation:

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The Reynolds number, rho VD/mu, is a very important parameter in fluid mechanics. Verify that the Reynolds number is dimensionle
Agata [3.3K]

Answer:

Re = 1 10⁴

Explanation:

Reynolds number is

         Re = ρ v D /μ

The units of each term are

       ρ = [kg / m³]

       v = [m / s]

      D = [m]

      μ = [Pa s]

The pressure

      Pa = [N / m²] = [Kg m / s²] 1 / [m²] = [kg / m s²]

      μ = [Pa s] = [kg / m s²] [s] = [kg / m s]

We substitute the units in the equation

      Re = [kg / m³] [m / s] [m] / [kg / m s]

      Re = [kg / m s] / [m s / kg]

      RE = [ ]

Reynolds number is a scalar

Let's evaluate for the given point

Where the data for methane are:

viscosity       μ = 11.2 10⁻⁶ Pa s

the density  ρ = 0.656 kg / m³

       D = 2 in (2.54 10⁻² m / 1 in) = 5.08 10⁻² m

       Re = 0.656 4 2 5.08 10⁻² /11.2 10⁻⁶

       Re = 1.19 10⁴

4 0
3 years ago
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