For this item, I assume that the speed being talked about is that of falling objects. If the object is farther away from the Earth's center, the gravitational energy will have very little effect on it. The speed will therefore be little less.
Answer:
The Michelson-Morley was designed to detect the motion of the earth through the ether.
No such relation was found and the speed of light is assumed to be the same in all reference frames.
For energy released from vaporisation,
Q(Energy) = m(mass of vapour) X l (latent heat of vaporisation)
= (0.65) X (2257)
You multiply force times friction
Answer: 0.47 rad/sec
Explanation:
By definition, the angular velocity is the rate of change of the angle traveled with time, so we can state the following:
ω = ∆θ/ ∆t
Now, we are told that in 13.3 sec, the ball completes one revolution around the circle, which means that, by definition of angle, it has rotated 2 π rad (an arc of 2πr over the radius r), so we can find ω as follows:
ω = 2 π / 13.3 rad/sec = 0.47 rad/sec