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jek_recluse [69]
3 years ago
11

An adult rhino xan have a mass of 1400 kg the mass of a small egret is about 0.76kg. what is the radio of these two masses? how

does this ratio compare to the ratio of the mass of a proton ti the mass of an electron?
Chemistry
1 answer:
serg [7]3 years ago
4 0

Answer:

The ratio of the mass of an adult rhino to the mass of a small egret is

(1400 kg)/(0.76 kg) = 1842.11

The ratio of the mass of a proton to the mass of an electron is

1836.15

The two ratios are very similar, the ratio of the masses of the proton to the electron being slightly smaller.

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A substance is tested in a lab. It is found to maintain a unique shape and is a good conductor of electricity. If it is made up
antoniya [11.8K]

Answer is: solid.

There are five fundamental states of matter (gas, liquid, solid, plasma and Bose–Einstein condensate).

In solid, molecules are closely packed, stiff and do not changes of shape or volume. Solid object (for example iron) does not take on the shape of its container.

Liquids have definite volume, but no fixed shape.

Gases (for example nitrogen and neeon) not have definite volume and fixed shape, it depends on its container.

Plasma is a an ionised gas with highly electrical conductivity.

6 0
3 years ago
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Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron fallsfrom the n = 7 to the n
Helga [31]

Answer:

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

Explanation:

We recall that Eₙ=\frac{-2.18*10^{-18} J}{n^{2} }

since there was transition from n7 to n=4 we will first calculate the change in the energy i.e ΔE

ΔE=E₄-E₇

ΔE=-2.18*10^{-18} J(\frac{1}{4^{2} } -\frac{1}{7^{2} } )

ΔE=-9.1760*10^-20 J

Now:

|ΔE|=Energy of photon=h*v=h*c/λ

λ=h*c/|ΔE|

λ=\frac{6.63*10^{-34}J.s*3.00*10^{8}m/s  }{9.1760*10^{-20} J }

λ=2.1676*10^-6 m

λ=2167.6*10^-9 m

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

5 0
3 years ago
HELPPPP I NEED THE ANSWER i'M STUCK
Tasya [4]

Answer:

carbon, nitrogen,oxygen,flourine

3 0
3 years ago
A compound made of two elements, iridium (Ir) and oxygen (O), was produced in a lab by heating iridium while exposed to air. The
natima [27]
1) Compund Ir (x) O(y)

2) Mass of iridium = mass of crucible and iridium - mass of crucible = 39.52 g - 38.26 g = 1.26 g

3) Mass of iridium oxide = mass of crucible and iridium oxide - mass of crucible = 39.73g - 38.26g = 1.47g

4) Mass of oxygen = mass of iridum oxide - mass of iridium = 1.47g - 1.26g = 0.21g

5) Convert grams to moles

moles of iridium = mass of iridium / molar mass of iridium = 1.26 g / 192.17 g/mol = 0.00656 moles

moles of oxygen = mass of oxygen / molar mass of oxygen = 0.21 g / 15.999 g/mol = 0.0131

6) Find the proportion of moles

Divide by the least of the number of moles, i.e. 0.00656

Ir: 0.00656 / 0.00656 = 1

O: 0.0131 / 0.00656 = 2

=> Empirical formula = Ir O2 (where 2 is the superscript for O)

Answer: Ir O2
5 0
3 years ago
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Can anyone help with number 8.
Stels [109]
A tornado! I think or it could be rain
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