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3 years ago

15

To get an accurate data reading, scientists must be sure to

1 answer:

joja [24]3 years ago

8 0

D.
Always use the right tool to get accurate measurements

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Describe the phenomenon of lightning?

masha68 [24]

Lightning is a naturally occurring electrostatic discharge during which two electrically charged regions in the atmosphere or ground temporarily equalize themselves, causing the instantaneous release of as much as one gigajoule of energy.

3 0

3 years ago

A firecracker in a coconut blows the coconut into three pieces. two pieces of equal mass fly off south and west, perpendicular t

kirill [66]

As per momentum conservation theory

If net force on a system is zero then initial momentum of the system will be equal to final momentum of that system.

Since initially coconut is at rest so initial momentum is zero

Here it break into three pieces such that two parts of same mass while third part is of double mass

now we can say

$P_1 + P_2 + P_3 = 0$

here we know that two parts fly off with same speed v0 along south and west directions

$mv_0 (-\hat j) + mv_0 (-\hat i) + 2m \vec v = 0$

now we will have

$\vec v = \frac{v_0}{2}\hat i + \frac{v_0}{2}\hat j$

so here magnitude of the speed of the third part will be

$|v| = \sqrt{(\frac{v_0}{2})^2+(\frac{v_0}{2})^2}$

$|v| = \frac{v_0}{\sqrt2}$

and the direction of the third part will be along North East direction

7 0

3 years ago

Read 2 more answers

A student performs this experiment and measures the bar to have a mass of 150g and length of 36cm. What is the moment of inertia

Ugo [173]

Answer:

The moment of inertia of the bar is $45\times10^{-4}\ kg-m^2$

Explanation:

Given that,

mass of bar = 150 g

Length l = 36 cm

We need to calculate the moment of inertia of the bar

Using formula of moment inertia

$I=\dfrac{1}{12}Ml^2$

Where,

M = mass of the bar

L = length of the bar

Put the value into the formula

$I=\dfrac{1}{12}\times150\times10^-3\times36\times10^{-2}$

$I=45\times10^{-4}\ kg-m^2$

Hence, The moment of inertia of the bar is $45\times10^{-4}\ kg-m^2$

4 0

3 years ago

Two 0.40 kg soccer ball collide elastically in a head-on collision. The first ball starts at rest, and the second ball has a spe

yulyashka [42]

Explanation:

Mass of two soccer balls, $m_1=m_2=0.4\ kg$

Initial speed of first ball, $u_1=0$

Initial speed of second ball, $u_2=3.5\ m/s$

After the collision,

Final speed of the second ball, $v_2=0$

(a) The momentum remains conserved. Using the conservation of momentum to find it as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$v_1$ is the final speed of the first ball

$0.4\times 0+0.4\times 3.5=0.4v_1+0.4\times 0$

$0.4\times 3.5=0.4v_1$

$v_1=3.5\ m/s$

(b) Let $E_1$ is the kinetic energy of the first ball before the collision. It is given by :

$E_1=\dfrac{1}{2}mu_1^2$

$E_1=\dfrac{1}{2}\times 0.4\times 0$

It is at rest, so, the kinetic energy of the first ball before the collision is 0.

(c) After the collision, the second ball comes to rest. So, the kinetic energy of the second ball after the collision is 0.

Hence, this is the required solution.

7 0

3 years ago

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A toy car sits motionless at the top of a ramp. What will happen to the car if a balanced force acts upon it?

dexar [7]

Answer:

kinetic energy because when the car moves again it will be faster then it was before

5 0

2 years ago