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Bingel [31]
3 years ago
9

Describe the phenomenon of lightning?​

Physics
1 answer:
masha68 [24]3 years ago
3 0

Lightning is a naturally occurring electrostatic discharge during which two electrically charged regions in the atmosphere or ground temporarily equalize themselves, causing the instantaneous release of as much as one gigajoule of energy.
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Help me its physical science and i don't know what to do tyyy​
miskamm [114]

The thing to do here is to balance the eqns that is to balance the stoichometric ratios or coefficients of the cpds.

hope you understand. all the best.

7 0
3 years ago
How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?
Viktor [21]

Answer:

F= 403429 kpa

Explanation:

Pressure is the product of force and area

Mathematically,

P=F*A -------where F is force and A is area.

A= 40 *0.1 = 4mm² -----convert to m²

A= 4e⁻⁶ m²

P= 4000000 pa

F= P/A = 4000000/4e⁻⁶

F= 403428793.493 pa

F= 403429 kpa

7 0
3 years ago
Even when the head is held erect, as in the figure below, its center of mass is not directly over the principal point of support
alexandr1967 [171]

We are asked to determine the force required by the neck muscle in order to keep the head in equilibrium. To do that we will add the torques produced by the muscle force and the weight of the head. We will use torque in the clockwise direction to be negative, therefore, we have:

\Sigma T=r_{M\perp}(F_M)-r_{W\perp}(W)

Since we want to determine the forces when the system is at equilibrium this means that the total sum of torque is zero:

r_{M\perp}(F_M)-r_{W\perp}(W)=0

Now, we solve for the force of the muscle. First, we add the torque of the weight to both sides:

r_{M\perp}(F_M)=r_{W\perp}(W)

Now, we divide by the distance of the muscle:

(F_M)=\frac{r_{W\perp}(W)}{r_{M\perp}}

Now, we substitute the values:

F_M=\frac{(2.4cm)(50N)}{5.1cm}

Now, we solve the operations:

F_M=23.53N

Therefore, the force exerted by the muscles is 23.53 Newtons.

Part B. To determine the force on the pivot we will add the forces we add the vertical forces:

\Sigma F_v=F_j-F_M-W

Since there is no vertical movement the sum of vertical forces is zero:

F_j-F_M-W=0

Now, we add the force of the muscle and the weight to both sides to solve for the force on the pivot:

F_j=F_M+W

Now, we plug in the values:

F_j=23.53N+50N

Solving the operations:

F_j=73.53N

Therefore, the force is 73.53 Newtons.

8 0
1 year ago
An 8 g bullet leaves the muzzle of a rifle with
Elena-2011 [213]

Answer: 1872 N

Explanation:

This problem can be solved by using one of the Kinematics equations and Newton's second law of motion:

V^{2}=V_{o}^{2} + 2ad (1)

F=ma (2)

Where:

V=611.9 m/s is the bullet's final speed (when it leaves the muzzle)

V_{o}=0 is the bullet's initial speed (at rest)

a is the bullet's acceleration

d=0.8 m is the distance traveled by the bullet before leaving the muzzle

F is the force

m=8 g \frac{1 kg}{1000 g}=0.008 kg is the mass of the bullet

Knowing this, let's begin by isolating a from (1):

a=\frac{V^{2}}{2d} (3)

a=\frac{(611.9 m/s)^{2}}{2(0.8 m)} (4)

a=234013.5063 m/s^{2} \approx 2.34(10)^{5} m/s^{2} (5)

Substituting (5) in (2):

F=(0.008 kg)(2.34(10)^{5} m/s^{2}) (6)

Finally:

F=1872 N

4 0
3 years ago
The battery charger for an mp3 player contains a step-down transformer with a turns ratio of 1:29, so that the voltage of 120 v
kifflom [539]
Transformer contains two coils: primary and secondary. They allow change of voltage to lower or higher value. In first case we have step-down and in second case we have step-up transformer.

Formula used for transformer is:
\frac{ N_{1} }{N_{2} } = \frac{ V_{1} }{V_{2} }

Where:
N1 = number of turns on primary coil
N2 = number of turns on secondary coil
V1 = voltage on primary coil
V2 = voltage on secondary coil

In a step-down transformer primary coil has more turns than secondary coil. So the ratio 1:29 means that for each turn on secondary coil we have 29 turns on primary coil.

We can solve the equation for V2:
{V_{2}}=\frac{ V_{1}{N_{2} }  }{N_{1} } \\  {V_{2}}=\frac{ 120*{x }  }{29x } \\  {V_{2}}=4.14V

Secondary coil provides voltage of 4.14V.
8 0
4 years ago
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