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Sphinxa [80]
3 years ago
13

The two types of glaciers are the U type which is found in the Rocky Mountains, and the L type which can be found in Switzerland

.
True

False
Physics
1 answer:
Arturiano [62]3 years ago
4 0
THE ANSWER IS TRUE
Have a nice day
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Can someone help me<br> Btw the last one say current
Sliva [168]
Magnitude: Magnitude generally refers to the quantity or distance.

Attraction: A force that makes things move together and stay together.

Repulsive: The feeling of being repelled, as by the thought or presence of something; distaste, repugnance, or aversion.

Current: Current is the rate of flow of electric charge. A potential difference (voltage) across an electrical component is needed to make a current flow through it.

I hope that helps :]
3 0
3 years ago
An object that is thrown straight up falls back to Earth. This is one-dimensional motion. (a) When is its velocity zero? (b) Doe
maw [93]

Answer:

Explanation:

(a) The velocity of object is zero when it is at maximum height.

(b) The direction of velocity changes as it starts moving downwards after it reaches the maximum height.

(c) Acceleration due to gravity always acts downwards so its sign remains same.

8 0
3 years ago
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Before proceeding into an intersection at a green signal, you should look out for:
Valentin [98]
B is correct but I’m not sure
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The ends of a massless rope are attached to two stationary objects (e.g., two trees or two cars) so that the rope makes a straig
julia-pushkina [17]

Answer: They are all true

a. The tension in the rope is everywhere the same.

b. The magnitudes of the forces exerted on the two objects by the rope are the same.

c. The forces exerted on the two objects by the rope must be in opposite directions.

d. The forces exerted on the two objects by the rope must be in the direction of the rope.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)  

- Cutiepatutie ☺❀❤

5 0
3 years ago
Consider a system two point charges. One has charge +q at (x, y,z) -(a,0,0) and another of charge-q at (x, y, z) = (-a, 0,0). 5.
olga2289 [7]

Answer:

electricfield at (0,0,0) is Et = 2 k q / a²

Explanation:

For the first part see the diagram , the field lines start from the positive charge and reach the negative charge, notice that no line should cross, some lines go to infinity

For the second part we use that the electric field is a vector quantity and therefore we add the field of each charge, using the equation

     E = k q / r²

Point (0,0,0)

We calculate for the charge -q which is at a distance R = a

   E1 = k (-q) / a²

   E1 = - kq / a²

As the test charge is positive in the field it goes to the left, attractive force

We calculate for the charge that is also at R = a

    E2 = k q / a²

This field goes to the left, repulsive force

We find the total electric field

    Et = E1 + E2

    Et = kq / a² + kq / a²

    Et = 2 k q / a²

Point (0,0, R)

We use the same equations, but with another distance, for the charge -q the distance is R = R+a and for the charge + q the distance is R = R-a

     E1 = k q / (R + a)²

     E2 = kq / (R-a)²

     Et = kq [1 / (R + a)² + 1 / (R-a)²]

     Et= kq {[(R-a)² + (R + a)²] / [(R + a)² (R-a)²]}

     Et= kq {2 (R² + a²) / [(R + a)² (R-a)²]}

If we use the condition that  R> a we can despise in the patents "a"

     (R² + a²) = R² (1+ a² / R²) ≈ R²

     (R + a)² = R² (1 + a / R)² ≈ R²

     (R- a)²  = R² (1-a / R)² ≈ R²

Substituting in the total electric field

     Et = kq {2 R²) / [R²R²]}

     Et =kq 2 / R²

7 0
3 years ago
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