Based on Le Chatelier's principle, when the equilibrium of a given reaction is disturbed due to some external factors like temperature, pressure or concentration, the equilibrium shifts in a direction to undo the effects of the change produced.
The given reaction is :-
CaCO3 (s) ↔ CaO (g) + CO2(g)
The forward reaction involves the formation of CaO and CO2 while the reverse involves formation of CaCO3.
If the concentration of the products CaO and CO2 is increased then the equilibrium will shift to a direction to counteract this increase. Hence, the products will tend to get used up and the reverse reaction will be favored.
Ans: B) the rate of reverse reaction will increase if the concentration of caO and CO2 is increased.
Each period corresponds to a principal energy level.
Answer:
Molarity=Moles of solute/volume of solution in Litres
Simply imputing your values
you have
0.75/65
0.0115M.
Answer:
Explanation:
Q = m × Cp × delta T
Where,
Q is the heat gained by water
m is the mass of water
Cp = specific heat capacity of water
= 4.18 kJ per kilogram per degree Celsius (J/kg°C).
This means that it takes 4,180 J to raise the temperature of 1 kg of water by 1°C
delta T is the difference in temperature
A.
The smaller beaker had a bigger temperature rise because the same energy has been given to a smaller number of water particles in the beaker than those particles in the large beaker so each particle is moving faster than those in the other beaker.
B.
Since both beakers were heated at the same time, they both gain the same amount of energy.
Qlarge = Qsmall