Answer:
The value of a + 2z/ 2 in terms of a is (3a+4)/2
Step-by-step explanation:
least of 3 consecutive integers is a, and the greatest is z
if a is the least one
we know that integers differ by value of 1.
example -2, -1, 0, 1,2
they all differ by
then next consecutive integer will be a+1
third integer will be second integer +1 = a+1 + 1 = a+2
Thus, 3 consecutive integer
a , a+1, a+2
but given that greatest is z
thus, a+2 is greatest and hence
a+2 = z
we have to find value of a + 2z/ 2 in terms of a
a + 2z/ 2 = a + 2(a+2)/2 = (a+ 2a +4)/2 = (3a+4)/2.
The value of a + 2z/ 2 in terms of a is (3a+4)/2
Answer:
44.2 years
Step-by-step explanation:
If we assume the interest is compounded annually and the investment is a one-time deposit into the account, its value each year is multiplied by 1+6.25% = 1.0625. After n years, the value in the account will be ...
19000 = 1300·1.0625^n
Dividing by 1300 and taking logs, we have ...
log(19000/1300) = n·log(1.0625)
log(190/13)/log(1.0625) = n ≈ 44.24 . . . . years
It will take about 44.2 years for the account to reach $19,000.
Tan(40)= x/20 => x= tan(40).20= 16,78
Ok done. Thank to me:>
