Question

What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K? The latent heat of vaporization of water is 2.25 x 10^6 J kg-1.

Answer 1

Answer : The mass of a sample of water is, 888.89 grams

Explanation :

Latent heat of vaporization : It is defined as the amount of heat energy released or absorbed when the liquid converted to vapor at atmospheric pressure at its boiling point.

Formula used :

$q=L\times m$

where,

q = heat = 2000 kJ = $2\times 10^6J$       (1 kJ = 1000 J)

L = latent heat of vaporization of water = $2.25\times 10^6J/kg$

m = mass of sample of water = ?

Now put all the given values in the above formula, we get:

$2\times 10^6J=(2.25\times 10^6J/kg)\times m$

$m=0.88889kg=888.89g$       (1 kg = 1000 g)

Therefore, the mass of a sample of water is, 888.89 grams