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elena-s [515]
3 years ago
14

Fossils can be body parts of ancient organisms, or they can be traces. Give five examples of traces. Help this is due today!!!!!

7 grade
Chemistry
1 answer:
SSSSS [86.1K]3 years ago
6 0

Burrows, tracks, coprolites, nests and footprints are examples of traces that can be found in a fossil.

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3. The doctor notices that Janet has long fingernails, and comments that fingernails grow at a rate (or
Viktor [21]

Answer:

7.93 × 10⁻¹³ km/s

Explanation:

Step 1: Given data

Rate of growth of the fingernails (r): 2.50 cm/year

Step 2: Convert "r" from cm/year to km/year

We will use the following conversion factors.

  • 1 m = 100 cm
  • 1 km = 1000 m

\frac{2.50cm}{year} \times \frac{1m}{100cm} \times \frac{1km}{1000m} = 2.50 \times 10^{-5} km/year

Step 3: Convert "r" from km/year to km/s

We will use the following conversion factors.

  • 1 year = 365 day
  • 1 day = 24 h
  • 1 h = 60 min
  • 1 min = 60 s

\frac{2.50 \times 10^{-5} km}{year} \times \frac{1year}{365day} \times \frac{1day}{24h} \times \frac{1h}{60min} \times \frac{1min}{60s} = 7.93 \times 10^{-13} km/s

2.50 cm/year is equal to 7.93 × 10⁻¹³ kilometers/second.

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2 years ago
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A 2.06g sample of agno3•xh2o is dissolved in an aqueous solution of excess nacl. The resulting agcl precipitate is filtered off
irakobra [83]

Answer:

3

Explanation:

NaCl + AgNO₃ ———> NaNO₃ + AgCl.

Firstly, we will need to calculate the number of moles of AgCl produced. That is equal to the mass produced divided by the molar mass of AgCl.

The molar mass of AgCl = 108 + 35.5 = 143.5g/mol

The number of moles is thus 1.32/143.5 = 0.0092 moles

Since silver nitrate and silver chloride contains one atom of silver, it is only possible that their mole ratios are equal. Hence we say that 0.0092 moles of silver nitrate hydrate was dissolved.

Now we go on to calculate the molar mass of the silver nitrate hydrate.

The molar mass is simply the mass divided by the number of moles.

That is 2.06/0.0092 = 223.9 = 224g/mol

We can now calculate the value of x from here.

AgNO3.xH2O

(108 + 14 + 48) + x(2+ 16) = 224

170 + 18x = 224

18x = 224 - 170 = 54

18x = 54

x = 54/18 = 3

8 0
3 years ago
How well can you apply Charles’s law to this sample of gas that experiences changes in pressure and volume? Assume that pressure
GarryVolchara [31]

Answer:

A: 384

B: 0.85

C: 1.1

D: 221

Explanation:

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