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babunello [35]
3 years ago
10

What causes some materials to have magnetic field

Physics
1 answer:
SOVA2 [1]3 years ago
3 0
Well correct me if im wrong, friction would be my answer
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Which factors are used to calculate the kinetic energy of an object? Check all that apply.
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Gravity and velocity
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3 years ago
A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma
tresset_1 [31]

Answer:

Explanation:

a. Given that:

m- mass of first & second piece, 3m-mass of 3rd piece,\bar v_1-velocity of first piece(-23\dot i \ m/s) and \bar v_2 as velocity of 2nd piece (-23\dot j \ m/s)

Let \bar v_3 be velocity of 3rd piece=?

#Vessel is at rest before explosion. Considering conservation of linear momentum:

m\bar v_1 +m\bar v_2 +3m \bar v_3=0   #Dividing both sides by m, m\neq 0

\bar v_1+ \bar v_2 +3\bar v_3=0\\3\bar v_3=-(\bar v_1 +\bar v_2)\\\bar v_3=-\frac{1}{3}(\bar v_1 +\bar v_2)

#Plug the\bar v_1 ,\bar v_2  values:

\bar v_3=-\frac{1}{3}(-23\dot i -23\dot j)=\frac{1}{3}(23\dot i +23\dot j)

#So the magnitude of the third piece is:

|\bar v_3|=\sqrt{(23/3)^2+(23/3)^2}\\=10.84m/s

Magnitude of the 3rd piece is 10.84 m/s

b. To find direction of the magnitude (as an angle relative to the x-axis), we find \angle \theta. The angle is obtained by getting the tan inverse as:

\theta=tan^-^1(\frac{23/3}{23/3})\\=45\textdegree

-The direction of the magnitude (angle relative to the x-axis) is 45°

6 0
3 years ago
Earth recycles water through select all that apply
Natasha2012 [34]

Answer:

evaporation to condensation to precipitation.

6 0
3 years ago
Read 2 more answers
How to change V=72km/hr to m/s
lapo4ka [179]
Multiply by (1000 meters / 1 km).
Then multiply by (1 hour / 3600 seconds).

Both of those fractions are equal to ' 1 ', because the top
and bottom numbers are equal, so the multiplications
won't change the VALUE of the 72 km/hr.  They'll only
change the units.

(72 km/hour) · (1000 meters / 1 km) · (1 hour / 3600 seconds)

= (72 · 1000 / 3600) (km·meter·hour / hour·km·second)

=  20 meter/second
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4 years ago
What is the process of preparing a person to perform strenuous work and to recover from that work as quickly as possible?
vesna_86 [32]
The process of preparing a person to perform strenuous work and to recover from that work as quickly as possible is called training, I bet. Such w<span>arm up exercises as  like stretching and other should lead person to the recovery. Hope it will help.</span>
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4 years ago
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