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statuscvo [17]
4 years ago
14

One gram of glass will rise 20° C when------------calories of heat are applied

Chemistry
1 answer:
astra-53 [7]4 years ago
6 0

Answer:

3.2 Calories

Explanation:

Here we will use a formula

Heat added in calories = Mass of glass x Increase in temperature x specific heat of glass  

As we know that, specific heat is the amount of energy required to raise the temperature of one gram of any substance by 1°C. It has a constant value for every substance and for glass the specific heat  is .16 calories/gm

Incorporating the values of mass (m), temperature(T) and  specific heat (c) in formula.

     calories (small calories) = l.0 g x 20 degrees x .16 calories/gm/°C

                                                      = 3.2 calories


Hope it helps:)

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2. A sample of neon gas has a volume of 87.6 L at STP. How many moles are present?
PSYCHO15rus [73]

Answer:

                      3.91 moles of Neon

Explanation:

According to Avogadro's Law, same volume of any gas at standard temperature (273.15 K or O °C) and pressure (1 atm) will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

                 n = moles = <u>???</u>

                 V = Volume = 87.6 L

Solution:

               As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

                          = ( 1 mole × 87.6 L) ÷ 22.4 L

                          = 3.91 moles

<h3>2nd Method:</h3>

                     Assuming that the gas is acting ideally, hence, applying ideal gas equation.

                              P V  =  n R T      ∴  R  =  0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹

Solving for n,

                              n  =  P V / R T

Putting values,

                              n  =  (1 atm × 87.6 L)/(0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15K)

                              n  =  3.91 moles

Result:

          87.6 L of Neon gas will contain 3.91 moles at standard temperature and pressure.

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Answer:

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Explanation:

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