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svp [43]
3 years ago
9

At what frequency f, in hertz, would you have to move the comb up and down to produce red light, of wavelength 600 nm

Physics
1 answer:
ratelena [41]3 years ago
3 0

Answer:

f = 500 x 10^12Hz

Explanation:

E=hc/wavelength

E=hf

hc/wavelength =hf

c/wavelength =f

f = 3 x 10^8 / 600 x 10^-9 = 500 x 10^12Hz

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A concave mirror is diverging mirror.true or false​
marissa [1.9K]

Answer:

true

Explanation:

it is concave when it diverging

4 0
3 years ago
How do i figure out this question?
nikklg [1K]

Answer:

0.75 g/cm^3

Explanation:

The formula for density:

\rho = \frac{m}{V}

Where m is the mass and V is the volume.

So, we can substitute values for m and V:

\rho = \frac{277}{370}\approx0.75

Therefore, the density is 0.75 g/cm^3 (watch the units!)

8 0
3 years ago
Read 2 more answers
When Karl Kaveman adds chilled grog to his new granite mug, he removes 10.9 kJ of energy from the mug. If it has a mass of 625 g
mrs_skeptik [129]

Answer:

3°C

Explanation:

We can that heat Q=mc_p dT

Where m is the mass c_p = specific heat capacity

dT = Temperature difference

here we have given m=625 g =.625 kg

specific heat of granite =0.79 J/(g-K) = 0.79 KJ/(kg-k)

T_1 =25°C

T_2 we have to find

we have also given Q=10.9 KJ

10.9=0.625×0.79×(25-T_2)

25-T_2 =22

T_2=3°C

7 0
3 years ago
Read 2 more answers
How do you think that changing the mass of the pendulum bob will affect the period of the pendulum swing?​
myrzilka [38]
(Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.)
5 0
3 years ago
An 100 kg object traveling at 50 m/s collides (perfectly inelastic) with a 50 kg object initially at rest.
qaws [65]

Answer:

Option C. 5,000 kg m/s

Explanation:

<u>Linear Momentum on a System of Particles </u>

Is defined as the sum of the momenta of each particles in a determined moment. The individual momentum is the product of the mass of the particle by its speed

P=mv

The question refers to an 100 kg object traveling at 50 m/s who collides with another object of 50 kg object initially at rest. We compute the moments of each object

m_1=(100\ kg)(50\ m/s)=5,000\ kg\ m/s

m_2=(50\ kg)(0\ m/s) = 0

The sum of the momenta of both objects prior to the collision is

P=5,000\ kg\ m/s+0\ kg\ m/s

\boxed{ P=5,000\ kg\ m/s}

7 0
3 years ago
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