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ruslelena [56]
3 years ago
14

The team monitoring a space probe exploring the outer solar system fi nds that radio transmissions from the probe take 2.53 hours

to reach earth. how distant (in meters) is the probe
Physics
1 answer:
Aleksandr-060686 [28]3 years ago
3 0
If you can observe, we are only given one parameter here which is the time. If you want to compute for the distance, you have to know the speed. The hint here is the 'radio transmissions'. All the information gathered by the probe from the space, is sent back to the Earth by electromagnetic waves. Hence, we must know the speed of electromagnetic waves. Since they are as fast as light, their speed is equal to 300 million meters per second. Then, we can finally determine the distance.

d = speed*time
d = (300×10⁶ m/s)(2.53 hours)

Since 1 hour = 3,600 seconds,

d = (300×10⁶ m/s)(2.53 hours)(3,600 seconds/1 hour)
d = 2.73×10⁻¹² m
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Answer:

d) It will be cut to a fourth of the original force.

Explanation:

The magnitude of the electrostatic force between the charged objects is

F=k\frac{q_1 q_2}{r^2}

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r is the separation between the two objects

In this problem, the initial distance is doubled, so

r' = 2r

Therefore, the new electrostatic force will be

F=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}(k\frac{q_1 q_2}{r^2})=\frac{1}{4}F

So, the force will be cut to 1/4 of the original value.

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7 0
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8 0
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A 3.0kg mass tied to a string
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Answer:

\boxed{\sf Tension \ in \ the \ string \ (T) = 3 \ kN}

Given:

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Uniform speed (v) = 20 m/s

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To Find:

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Explanation:

Tension (T) is the string will be equal to centripetal force (\sf F_c).

\boxed{ \bold{ T = F_c  =  \frac{m {v}^{2} }{r} }}

Substituting value of m, v & r in the equation:

\sf \implies T =  \frac{3 \times  {20}^{2} }{0.4}  \\  \\  \sf \implies T = \frac{3 \times 400}{0.4}  \\  \\  \sf \implies T =3 \times 1000 \\  \\  \sf \implies T =3000 \: N \\  \\ \sf \implies T =3 \: kN

\therefore

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3 years ago
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Answer:

Drag or air resistance

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