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4 years ago

Which of the following is a mixture: a. air c. water b. salt d. sulfur

1 answer:

3 0

A. Air because is composed of different elements such as nitrogen, oxygen, water vapor, carbon dioxide, sulfur, argon and many others.

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What is meant by the statement '' density of water is 1000 kilograms per cubic metre ''?

LenKa [72]

It means that if you had a cubic meter of water it would weigh 1000 kilograms

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4 years ago

A salt is dissolved in water which has a freezing point of 0 degrees celsius. the freezing point of the solution would be

balandron [24]

A salt is dissolved in water which has a freezing point of 0 degrees celsius. the freezing point of the solution would be dependent on the concentration of the salt in the solution. It is explained by the colligative properties. These <span>are </span>properties<span> that depend upon the concentration of solute molecules or ions, but not upon the identity of the solute. Hope this answers the question.</span>

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3 years ago

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A rock is thrown down from the top of a cliff with a velocity of 3.61 m/s (down). The cliff is 28.4 m above the ground. Determin

Katarina [22]

I’m not sure look it up in the internet!

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3 years ago

Using the image provided, which moon phase is next?

ella [17]

Answer:

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3 years ago

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Assuming a 8 kilogram bowling ball moving at 2 m/s bounces off a spring at the same speed that had before bouncing what is the a

Naya [18.7K]

a) 32 kg m/s

Assuming the spring is initially at rest, the total momentum of the system before the collision is given only by the momentum of the bowling ball:

$p_i = m u = (8 kg)(2 m/s)=16 kg m/s$

The ball bounces off at the same speed had before, but the new velocity has a negative sign (since the direction is opposite to the initial direction). So, the new momentum of the ball is:

$p_{fB}=m v_b =(8 kg)(-2 m/s)=-16 kg m/s$

The final momentum after the collision is the sum of the momenta of the ball and off the spring:

$p_f = p_{fB}+p_{fS}$

where $p_{fS}$ is the momentum of the spring. For the conservation of momentum,

$p_i = p_f\\p_i = p_{fB}+p_{fS}\\p_{fS}=p_i -p_{fB}=16 kg m/s -(-16 kg m/s)=32 kg m/s$

b) -32 kg m/s

The change in momentum of bowling ball is given by the difference between its final momentum and initial momentum:

$\Delta p=p_{fb}-p_i=-16 kg m/s - 16 kg m/s=-32 kg m/s$

c) 64 N

The change in momentum is equal to the product between the average force and the time of the interaction:

$\Delta p=F \Delta t$

Since we know $\Delta t=0.5 s$ , we can find the magnitude of the force:

$F=\frac{\Delta p}{\Delta t}=\frac{-32 kg m/s}{0.5 s}=-64 N$

The negative sign simply means that the direction of the force is opposite to the initial direction of the ball.

d) The force calculated in the previous step (64 N) is larger than the force of 32 N.

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3 years ago