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Tresset [83]
3 years ago
7

Problem: In each of the following situations, what type of filtration device would you use?

Chemistry
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:

A. Filtration by gravity

B. Syringe filter

C. Syringe filter

D. Filtration by gravity

E. Syringe filter

F. Filtration by gravity / Vacuum filtration.

Explanation:

Filtration is a mixture of separation techniques to separate solids from liquids. The filtration can be done by gravity, by pressure or by vacuum. The correct filtration is chosen by the characteristics of the mixture.

A. The particles are big, so it's possible to use a funnel and a filter paper with the right numeration (the diameter of the pores must be smaller than the particles). The filtration will happen by gravitation.

B. Because the volume is too small (1 mL), it can be used as a syringe filter, a small device in which the solution is put in the syringe, and then, by pressure, the solution goes from the filter. Thus, the filtration is done by pressure.

C. As letter B, the small volume indicates a pressure filtration by a syringe filter.

D. In this case, such as letter A, it's possible to use gravitation filtration.

E. Because of the volume is too small, such as letters B and C, the pressure filtration by a syringe filter is more indicate.

F. In this case, the filtration can be done by gravitation, and a vacuum can be added to accelerate it because is a small volume with solid impurities.

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<em />

First, we need to find pKa of NH₃ using Kb. Then, the moles of NH₃ and finally replace these values in H-H equation to solve moles of NH₄Cl we need to obtain the desire pH.

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pKb = - log Kb

pKb = -log 1.8x10⁻⁵ = <em>4.74</em>

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<em>2.00L ₓ (0.200mol NH₃ / L) = 0.400 moles NH₃</em>

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pH = pKa + log [NH₃] / [NH₄Cl]

8.20 = 9.26 + log [0.400 moles] / [NH₄Cl]

-1.06 =  log [0.400 moles] / [NH₄Cl]

0.0087 =  [0.400 moles] / [NH₄Cl]

[NH₄Cl] = 0.400 moles / 0.0087

[NH₄Cl] = 4.59 moles of NH₄Cl we need to add to original solution to obtain a pH of 8.20. In grams (Using molar mass NH₄Cl=53.491g/mol):

4.59 moles NH₄Cl ₓ (53.491g / mol) =

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