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Tresset [83]
3 years ago
7

Problem: In each of the following situations, what type of filtration device would you use?

Chemistry
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:

A. Filtration by gravity

B. Syringe filter

C. Syringe filter

D. Filtration by gravity

E. Syringe filter

F. Filtration by gravity / Vacuum filtration.

Explanation:

Filtration is a mixture of separation techniques to separate solids from liquids. The filtration can be done by gravity, by pressure or by vacuum. The correct filtration is chosen by the characteristics of the mixture.

A. The particles are big, so it's possible to use a funnel and a filter paper with the right numeration (the diameter of the pores must be smaller than the particles). The filtration will happen by gravitation.

B. Because the volume is too small (1 mL), it can be used as a syringe filter, a small device in which the solution is put in the syringe, and then, by pressure, the solution goes from the filter. Thus, the filtration is done by pressure.

C. As letter B, the small volume indicates a pressure filtration by a syringe filter.

D. In this case, such as letter A, it's possible to use gravitation filtration.

E. Because of the volume is too small, such as letters B and C, the pressure filtration by a syringe filter is more indicate.

F. In this case, the filtration can be done by gravitation, and a vacuum can be added to accelerate it because is a small volume with solid impurities.

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Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

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Let us assume that x concentration of N_{2}O_{4} is present at the initial stage. Therefore, according to the ICE table,

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Now, expression for K_{p} of this reaction is as follows.

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Putting the given values into the above formula as follows.

          K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

                 2 = \frac{(0.2)^{2}}{(x - 0.1)}

                2 \times (x - 0.1) = (0.2)^{2}

                            x = 0.12

This means that P_{N_{2}O_{4}} = x = 0.12 atm.

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