1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Amanda [17]
4 years ago
11

Who wants a metal?

Chemistry
2 answers:
tiny-mole [99]4 years ago
8 0

Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?

A. Both have the same molar mass.

B. Both have the same number of ions.

C. Both are made up of 6.02 mc014-1 1023 molecules.

D. Both are made up of 6.02 mc014-2 1023 formula units.

The correct answer on E.D.G is ---Both are made up of 6.02 mc014-2 1023 formula units. D

Veronika [31]4 years ago
4 0

Answer: Option (d) is the correct answer.

Explanation:

A formula unit is basically empirical formula of a compound which tells us how  many atoms of one element are combining with how many atoms of another element.

For example, empirical formula of sodium chloride is NaCl. So, basically it shows that one atom of sodium is reacting with one atom of chlorine.

Also according to Avogadro, there are 6.022 \times 10^{23} atoms present in 1 mole of each substance.

Thus, we can conclude that both are made up of 6.022 \times 10^{23} formula units best compares 1 mol of sodium chloride to 1 mol of aluminum chloride.

You might be interested in
Urgent 25 points!!
LekaFEV [45]

Answer:

A. Yes, Amanda find the number of moles of NaCl correctly.

B. 0.73 M.

Explanation:

<em>A. Did Amanda find the number of moles of NaCl correctly? If not, explain. </em>

  • Yes, Amanda find the number of moles of NaCl correctly.
  • The relation to find the no. of moles of NaCl is:

<em>No. of moles (n) of NaCl = mass/molar mass.</em>

mass of NaCl = 32.0 g, molar mass of NaCl = 58.45 g/mol.

∴ No. of moles (n) of NaCl = mass/molar mass = (32.0 g)/(58.45 g/mol) = (32.0 g NaCl)*(1 mol of NaCl)/(58.45 g NaCl) = 0.547 mol ≅ 0.55 mol.

<em>B. What does Amanda need to do next to calculate the molarity of the NaCl solution? Show your work for full credit.</em>

<em></em>

  • Molarity is the no. of moles of solute dissolved in a 1.0 liter of a solution.

∴ M = (no. of moles of NaCl)/(volume of solution (L)) = (0.55 mol)/(0.75 L) = 0.73 M.

5 0
4 years ago
As a part of a clinical study, a pharmacist is asked to prepare a modification of a standard 22g package of a 2% mupirocin ointm
Vesna [10]

Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

mupirocin by weight = 2%

so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g

so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

mg of mupirocin powder are required = ?, lets rep this with x

Total weight of ointment = 22 + x g

Amount of mupirocin  = 0.44 + x g

percentage of mupirocin  in ointment is 3?

so

3/100 = 0.44 + x g / 22 + x g

3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

x mg  = 226.8 mg

Therefore, 226.8 mg of mupirocin powder are required

8 0
3 years ago
An inflated balloon contains X air molecules.After some time the volume of the balloon is found to be the half at the same tempe
sladkih [1.3K]

Answer:

See explanation

Explanation:

According to Avogadro's law, the volume of a given mass of gas is directly proportional to the number of molecules of gas present at constant temperature and pressure.

Hence; V1/n1 = V2/n2

The implication of this is, if there were X molecules present and the volume of the balloon is halved, the number of molecules of gas present is also halved. So, we now have X/2 number of gas molecules present in the balloon.

This is in accordance with the statement of Avogadro's law.

8 0
3 years ago
Which of he following is a secondary alkanol?
hodyreva [135]

Answer: Thus CH_3CH(OH)CH_3 is a secondary alkanol.

Explanation:

Alkanol are compounds which contains carbons bonded by single bonds and contains hydroxy (-OH) as functional group.

Primary alkanol are those compounds which contain hydroxyl group attached a carbon which is further attached to a single carbon atom. Example: CH_3CH_2CH_2OH and CH_3CH_2CH_2CH_2OH

Secondary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to two more carbon atoms.Example: CH_3CH(OH)CH_3

Tertiary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to three more carbon atoms. Example: C(CH_3)_3OH

Thus CH_3CH(OH)CH_3 is a secondary alkanol.

5 0
3 years ago
Pls help, WILL MARK BRAINLIEST FOR THE CORRECT ANSWER!!!!
Nitella [24]

Answer:

The answer is D. Substances Y and Z would react to replace substance W, and the position of equilibrium would shift to the left.

Explanation:

PLZ BRAINLIEST'!!!

6 0
3 years ago
Read 2 more answers
Other questions:
  • What is the symbol for the isotope of 58co that possesses 33 neutrons?
    15·1 answer
  • A sample from solution a and solution b were each tested with blue colored glucose indicator solution before the solutions were
    14·1 answer
  • Description for speed
    6·1 answer
  • When magnesium OMg) and sulfur (5) bond, what would be the charge of magnesium after the bond is made?
    8·1 answer
  • When the temperature is increased, what does not change?
    6·1 answer
  • Ammonium sulfate (NH4)2SO4 is made by reacting 25.0 L of 3.0 mol/L H2SO4 with 3.1× 103 L of NH3 at a pressure of 0.68 atm and a
    14·1 answer
  • What type of chemical reaction is 2C₄H₁₀ + 13O₂ ---&gt; 8CO₂ + 10H₂O?
    11·1 answer
  • How r u? do u like anime?
    10·2 answers
  • Hii can someone help me pls this is the last question
    8·1 answer
  • Explain the difference between a base and an alkali.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!