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Charra [1.4K]
3 years ago
9

Place the following types of attraction weakest to strongest:

Chemistry
1 answer:
avanturin [10]3 years ago
5 0

Answer: The order from weakest to strongest is:

\text{dispersion forces}

Explanation:

Dispersion force is the weakest intermolecular force. It is a temporary attractive force that come into action when the electrons in two neighboring atoms are at the positions which results in formation of temporary dipoles.

Dipole interaction is an attractive interaction between the positive end and negative end of the polar molecule.

Hydrogen bond is a weak bond between two adjacent molecules due to an electrostatic attraction between a hydrogen atom in a molecule with an electronegative atom of an adjacent molecule.

Single covalent bond is more stronger bond than the the interaction stated above because there is sharing of an electron between two atoms.

Ionic bond is the strongest bonds in which complete transfer of electrons is present. Due to high electronegativity difference between the bonded atoms there is a high electrostatic interaction between the oppositely charged ions which makes ionic bond strongest from all the other types of the bonds.

So, the order is:

\text{dispersion forces}


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Glucose is a simple sugar. It would most likely be found in which of the following foods?
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The dissociation of calcium carbonate has an equilibrium constant of Kp= 1.20 at 800°C. CaCO3(s) ⇋ CaO(s) + CO2(g)
Fed [463]

Explanation:

(a)   Formula that shows relation between K_{c} and K_{p} is as follows.

                 K_c = K_p \times (RT)^{-\Delta n}

Here, \Delta n = 1

Putting the given values into the above formula as follows.

        K_c = K_p \times (RT)^{-\Delta n}

                  = 1.20 \times (RT)^{-1}

                  = \frac{1.20}{0.0820 \times 1073}

                  = 0.01316

(b) As the given reaction equation is as follows.

               CaCO_{3}(s) \rightleftharpoons CaO(s) + CO_{2}(g)

As there is only one gas so ,

                p[CO_{2}] = K_{p} = 1.20

Therefore, pressure of CO_{2} in the container is 1.20.

(c)   Now, expression for K_{c} for the given reaction equation is as follows.  

             K_{c} = \frac{[CaO][CO_{2}]}{[CaCO_{3}]}

                        = \frac{x \times x}{(a - x)}

                        = \frac{x^{2}}{(a - x)}[/tex]

where,    a = initial conc. of CaCO_{3}

                  = \frac{22.5}{100} \times 9.56

                  = 0.023 M

          0.0131 = \frac{x^{2}}{0.023 - x}

                  x = 0.017

Therefore, calculate the percentage of calcium carbonate remained as follows.

       % of CaCO_{3} remained = (\frac{0.017}{0.023}) \times 100

                                  = 75.46%

Thus, the percentage of calcium carbonate remained is 75.46%.

3 0
4 years ago
How many liters of hydrogen gas I needed to react with CS2 to produce 2.5 L of CH4 At STP
olchik [2.2K]

Answer:

9.8 L

Explanation:

The reaction that takes place is:

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At STP, 1 mol of any gas occupies 22.4 L.

We <u>calculate how many moles are there in 2.5 L of CH₄ at STP</u>:

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Then we <u>convert CH₄ moles into H₂ moles</u>, using the<em> stoichiometric coefficients of the reaction</em>:

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Answer:

See explanation

Explanation:

Step 1: Data given

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Kc = [H2]^41 * [CS2] / [H2S]²*[CH4]

d. 2CO(g) + O2(g) ⇄ 2CO2(g)

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The answer is not in the choices. You only use Hvap if you boil water.
5 0
4 years ago
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