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Yanka [14]
4 years ago
15

If two teams playing tug-of-war pull on a rope with equal but opposite forces, what is the net external force on the rope?

Physics
1 answer:
Rashid [163]4 years ago
3 0
0, Because if they are pulling with equal force then they cancel each other out<span />
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For each of the following velocity vectors, give the vector component, the scalar component, and the magnitude. (a) v = 48.0j m/
Oduvanchick [21]

Obtaining the component part of the letter 'i' warns that it is the velocity is oriented on the X axis. At the same time the numeric part, in this particular case will represent the scalar part and therefore the magnitude of the vector.

The velocity is

\vec{v} = 48.0\hat{i} \text{ m/s }

The vector component of the velocity is

v_x = 48.0m/s

The scalar component of the velocity is

v = 48.0m/s

The magnitude of the velocity is

v = 48.0m/s

3 0
4 years ago
Anika asks Eva to roll a basketball and then a bowling ball to her. Which requires more force to roll, and why?
Paul [167]

It's easy to roll the the basket ball than bowling ball

It is because bowling ball is solid spherical ball which will have less moment of inertia

its moment of inertia is given as

I = \frac{2}{5}mR^2

While for the hollow ball like basketball we know that moment of inertia is given as

I' = \frac{2}{3}mR^2

so here we can see for the same mass if we take basketball then its moment of inertia is more so it is easy to roll basket ball then to roll bowling ball.

So it is easy to roll basket ball then rolling ball

6 0
4 years ago
Read 2 more answers
What height will the object reach? 12 points. Will give brainliest.
umka21 [38]

Answer:

12.7 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 56.7 Km/hr

Maximum height (h) =..?

First, we shall convert 56.7 Km/hr to m/s. This can be obtained as follow:

Initial velocity (m/s) = 56.7 x 1000/3600

Initial velocity (m/s) = 15.75 m/s

Next, we shall determine the time taken to get to the maximum height. This can be obtained as follow:

Initial velocity (u) = 15.75 m/s

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

v = u – gt (since the ball is going against gravity)

0 = 15.75 – 9.8 × t

Rearrange

9.8 × t = 15.75

Divide both side by 9.8

t = 15.75/9.8

t = 1.61 secs.

Finally, we shall determine the maximum height as follow

h = ½gt²

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 1.61 secs.

Height (h) =..?

h = ½gt²

h = ½ × 9.8 × 1.61²

h = 4.9 x 1.61²

h = 12.7 m

Therefore, the maximum height reached by the ball is 12.7 m

3 0
3 years ago
The speed of sound in water is measured to be 1485 m/s. what is this in mph?
ZanzabumX [31]
It will bw ugh 3500mph in 
6 0
3 years ago
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List the steps involved in the nitrogen cycle
Nesterboy [21]
Nitrogen fixation (N2 to NH3/ NH4+ or NO3-)
Nitrification (NH3 to NO3-)
Assimilation (Incorporation of NH3 and NO3- into biological tissues)Ammonification (organic nitrogen compounds to NH3)
<span>Denitrification(NO3- to N2)

its on google</span>
4 0
4 years ago
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