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pav-90 [236]
3 years ago
11

If a car generates 18hp (which is 13428Watts) when traveling at a steady speed of 88km/h (which is 24.44m/s), what must be the a

verage force exerted on the car due to friction and air resistance?
Physics
2 answers:
Murrr4er [49]3 years ago
8 0
<span>Power = Force * Velocity </span>

<span>First convert to SI units: </span>
<span>88 km/h = 24.44 m/s </span>
<span>18 Hp = 13,428 Watts </span>

<span>Force = P/V = 549 newtons</span>
Arturiano [62]3 years ago
3 0

Answer:

Explanation:

549N

parameters given

power generated by car, P = 18hp =13428W

steady speed , S = 24.44m/s

force, F = ?

For a car that is moving with steady speed (constant). Power the car generates is what it used to overcome force of friction. so

P = F X S

making P the subject of the formula

F = P/S

using the SI unit

= 13428/24.44

F = 549N

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How should variables be depicted on a graph?
nignag [31]

Answer:

D.) independent variable on the x-axis

Explanation:

Normally in an x-y plane, the value of x is taken as an independent variable, i.e. it is independent because it can assume any value (real number), while y depends on the value x. for example for the following equation.

y = x

Where:

x = independent value.

y = dependent value of x

This is the equation of a line, inclined with slope equal to 1.

4 0
3 years ago
A 0.208 kg particle with an initial velocity of 1.26 m/s is accelerated by a constant force of 0.766 N over a distance of 0.195
eduard

Answer:

Explanation:

Initial kinetic energy of particle

= 1/2 m V²

= .5 x .208 x 1.26²

= .165 J

Work done by force = force x displacement

= .766 x .195

= .149 J

This energy will be added up .

Total final kinetic energy

= initial kinetic energy + work done on the particle

= .165 + .149 J

=  .314 J .

3 0
3 years ago
What contains ribbon-like layers<br> A. Igneous <br> B. Sedimentary <br> C. Metamorphic
Pepsi [2]
B. Sedimentary Rocks
4 0
3 years ago
Show that any three linear operators A, B, and Ĉ satisfy the following (Ja- cobi) identity (10 pt) [[A, B] Ĉ] + [[B,C), A] + [[C
DerKrebs [107]

Answer:

Three linear operators A,B, and C will satisfy the condition [[A, B],C] + [[B,C), A] + [[C, A], B] = 0.

Explanation:

According to the question we have to prove.

[[A, B],C] + [[B,C), A] + [[C, A], B] = 0

Now taking Left hand side of the equation and solve.

[[A, B],C] + [[B,C), A] + [[C, A], B]

Now use commutator property on it as,

=[A,B] C-C[A,B]+[B,C]A-A[B,C]+[C,A]B-B[C,A]\\=(AB-BA)C-C(AB-BA)+(BC-CA)A-A(BC-CB)+(CA-AC)B-B(CA-AC)\\=ABC-BAC-CAB+CBA+BCA-CAB-ABC+ACB+CAB-ACB-BCA+BAC\\=0

Therefore, it is proved that [[A, B],C] + [[B,C), A] + [[C, A], B] = 0.

7 0
3 years ago
the gravitational force that earth exerts on the moon equals 2.03 x 10^20N. The moons mass is 7.35 x 10^22kg. What is the accele
Ghella [55]

The first time we read this, we think that we'll have to go look up a bunch of stuff about the gravitational constant, centripetal force, orbital mechanics, the Moon's period of revolution, and who knows whut owl !

But you know whut ?  The only thing we need is Newton's 2nd law:

F = m A

Divide each side by m :

Acceleration = Force / mass

Acceleration = (2.03 x 10²⁰ Newtons) / (7.35 x 10²² kg)

Acceleration = (2.03 x 10²⁰ / 7.35 x 10²² kg) (m/s²)

<em>Acceleration = 0.00276 m/s²</em>


8 0
3 years ago
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