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zloy xaker [14]
4 years ago
10

The angle formed between the SAI and the camber line is called the

Engineering
1 answer:
hichkok12 [17]4 years ago
8 0

Answer:C

Explanation:

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Explain how you could transmit two independent base-band information signals by using SSB on a common carrier frequency.
Goshia [24]

Answer:

Using Hilbert Transformation, we can transmit two independent base-band information signals by using SSB on a common-carrier frequency.

Explanation:

  • In SSB modulators, we pre-process a real signal  by Hilbert Transform filter to form another real signal
  • The signal has the same spectral amplitude but has 90° phase shift at each frequency relative to its input signal.
  • The ordered pair gets almost all of its negative components cancelled
  • thus, with the use of Hilbert Transformation, we can transmit two independent base-band information signals by using SSB on a common carrier frequency.

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Y_Kistochka [10]

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yes

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Determine the specific volume of superheated water vapor at 15 MPa and 350°C, using a. The ideal-gas equation Answer: 0.01917 m3
ollegr [7]

Answer:

specific volume by ideal gas equation = 0.01917 m³/kg

specific volume by compressibility chart = 0.01246 m³/kg

specif volume by super heated stream table is 0.0114810 m³/kg

Explanation:

given data

temperature  T = 350°C = 623 K

pressure P = 15 MPa = 15000 kPa

to find out

specific volume by  ideal-gas equation ,generalized compressibility chart and steam tables

solution

we will apply here ideal gas equation that is

specific volume = \frac{R*T}{P}   ..............1

here P is pressure and T is temperature and R is gas constant i.e 0.4615 kJ/kg-K

specific volume =  \frac{0.4615*623}{15000}

specific volume = 0.01917 m³/kg

and

by the compressibility chart

critical pressure of water Pcr = 22.06 Mpa

and critical temperature of water Tcr = 647.1 K

so

reduced pressure will be = \frac{P}{Pcr}

reduced pressure = \frac{15}{22.06} = 0.68 Mpa

and

reduced temperature will be = \frac{T}{Tcr}

reduced pressure = \frac{623}{647.1} = 0.963 K

so by compressibility chart pressure 0.68 Mpa and temperature 0.963 K

compressibility factor Z is 0.65

so

specific volume = compressibility factor Z × ideal specific volume

specific volume = 0.65 × 0.01917

specific volume = 0.01246 m³/kg

and

by the steam table

use here super heated stream table for

pressure = 15 Mpa

ans temperature = 350°C

so

specif volume by super heated stream table is 0.0114810 m³/kg

6 0
4 years ago
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