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tia_tia [17]
3 years ago
8

A hydraulic cylinder has a 125-mm diameter piston with hydraulic fluid inside the cylinder and an ambient pressure of 1 bar. Ass

uming standard gravity, find the piston mass that will create a pressure inside of 2500 kPa.
Engineering
1 answer:
gulaghasi [49]3 years ago
6 0

Answer: 3002.86kg

Explanation:

Hydraulic cylinder diameter =125mm

Ambient pressure =1bar

Pressure =2500kpa

Piston Mass (MP) =?

F|(when it moves upward )=PA=F|(when it moves downward) =PoA+Mpg

Po=1 bar=100kpa

A=(π/4)D^2=(π/4)*0.125^2=0.01227m^2

Mp=(P-Po) A/g=(2500-100)*1000*0.01227/9.80665

Mp=3002.86kg.

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2 years ago
Ai r is compressed by a 30-kW compressor from P1 to P2. The air t emperature i s maintained constant at 25oC during thi s proces
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The rate of entropy change of the air is -0.10067kW/K

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3 0
3 years ago
A cylindrical resistor element on a circuit board dissipates 0.6 W of power. The resistor is 1.5 cm long, and has a diameter of
Burka [1]

Answer:

a. 51.84Kj

b. 2808.99 W/m^2

c. 11.75%

Explanation:

Amount of heat this resistor dissipates during a 24-hour period

= amount of power dissipated * time

= 0.6 * 24 = 14.4 Watt hour

(Note 3.6Watt hour = 1Kj )

=14.4*3.6 = 51.84Kj

Heat flux = amount of power dissipated/ surface area

surface area = area of the two circular end  + area of the curve surface

=2*\frac{\pi D^{2} }{4} + \pi DL\\=2*\frac{\pi *(\frac{0.4}{100} )^{2} }{4} + \pi *\frac{0.4}{100} *\frac{1.5}{100}

= 2.136 *10^-4 m^{2}

Heat flux =\frac{0.6}{2.136 * 10^{-4} } = 2808.99 W/m^{2}

fraction of heat dissipated from the top and bottom surface

=\frac{\frac{2*\pi D^{2} }{4} }{\frac{2*\pi D^{2}}{4} + \pi DL } \\\\=\\\frac{\frac{2*\pi *(\frac{0.4}{100} )^{2} }{4} }{\frac{2*\pi *(\frac{0.4}{100}  )^{2} }{4} +\pi *\frac{0.4}{100} *\frac{1.5}{100} } \\\\=\frac{2.51*10^{-5} }{2.136*10^{-4} } \\\\\= 0.1175

=11.75%

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3 years ago
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