In order to comply with the used oil rule,a facility must properly manage its oil-contaminated sorbents (I.e. , don’t mix other wastes with these sorbets) and it must either recycle sorbets or send them for disposal at a permitted facility that burn them for energy recovery.
Answer:
The maximum allowable distance = 5 m
Explanation:
Data:
There will be three forces on the jib. Let the forces be denoted as:
,
and the force on pole AB
To find the angle AB makes with the horizontal beam:

The load has a mass of 2 000 kg then, the force will be:
F = mg, where g = 9.81 m/s²
= 
Breaking AB into its x and y coordinates:

Then,
∑
= 0

∑
∑
so the components of the forces will be 30 656.2 N and - 3 372.18 N
Answer:
<em>A) depends on the polarities of the armature and field currents.</em>
Explanation:
In the DC series motor, or a universal motor, the field and armature winding are connected in series. This means that if the polarity of the input DC voltage is changed, the direction of the field & armature will also change, resulting in the change of direction of rotation of the motor. This means that the direction of rotation of a DC series motor, or a universal motor connected to a DC power source can be reversed by changing the polarity of the field current, or the armature current.
Answer:
D) 1.04 Btu/s from the liquid to the surroundings.
Explanation:
Given that:
flow rate (m) = 2 lb/s
liquid specific enthalpy at the inlet (
Btu/lb)
liquid specific enthalpy at the exit (
Btu/lb)
initial elevation (
)
final elevation (
)
acceleration due to gravity (g) = 32.174 ft/s²
= 3 Btu/s
The energy balance equation is given as:
![Q_{cv}-W{cv}+m[(h_1-h_2)+(\frac{V_1^2-V_2^2}{2})+g(z_1-z_2)]=0](https://tex.z-dn.net/?f=Q_%7Bcv%7D-W%7Bcv%7D%2Bm%5B%28h_1-h_2%29%2B%28%5Cfrac%7BV_1%5E2-V_2%5E2%7D%7B2%7D%29%2Bg%28z_1-z_2%29%5D%3D0)
Since kinetic energy effects are negligible, the equation becomes:
![Q_{cv}-W{cv}+m[(h_1-h_2)+g(z_1-z_2)]=0](https://tex.z-dn.net/?f=Q_%7Bcv%7D-W%7Bcv%7D%2Bm%5B%28h_1-h_2%29%2Bg%28z_1-z_2%29%5D%3D0)
Substituting values:
![Q_{cv}-(-3)+2[(40.09-40.94)+\frac{32.174(0-100)}{778*32.174} ]=0\\Q_{cv}+3+2[-0.85-0.1285 ]=0\\Q_{cv}+3+2(-0.9785)=0\\Q_{cv}+3-1.957=0\\Q_{cv}+1.04=0\\Q_{cv}=-1.04\\](https://tex.z-dn.net/?f=Q_%7Bcv%7D-%28-3%29%2B2%5B%2840.09-40.94%29%2B%5Cfrac%7B32.174%280-100%29%7D%7B778%2A32.174%7D%20%5D%3D0%5C%5CQ_%7Bcv%7D%2B3%2B2%5B-0.85-0.1285%20%5D%3D0%5C%5CQ_%7Bcv%7D%2B3%2B2%28-0.9785%29%3D0%5C%5CQ_%7Bcv%7D%2B3-1.957%3D0%5C%5CQ_%7Bcv%7D%2B1.04%3D0%5C%5CQ_%7Bcv%7D%3D-1.04%5C%5C)
The heat transfer rate is 1.04 Btu/s from the liquid to the surroundings.
What you mean?? .!.!.!.!!.