Answer:
d. W<0 and Q<0
Explanation:
Heat (Q) and work (W) are ways of exchange of energy.
When a system gains heat, that its temperature increases, and, because the heat flows to the system it's positive (Q>0), and when it loses heat the inverse happens and Q<0.
When the system expands, it does work at the surroundings, so the work is going from the system, and it's positive (W >0), when the inverse happens, the work goes to the system and W<0.
So, the gas is compressed, then W<0, and it warms up. To cold it, the tank has put a tub with water, do the gas will lose heat and Q<0.
The experiments that claimed to demonstrate cold fusion were found
to have been faulty by others who reviewed them. Also, nobody else
was
able to reproduce the finding in other laboratories. In the world
of
Science, this pretty much says that the initial claims were unfounded.
Answer:
6926.4J
Explanation:
Given parameters:
Mass of iron = 200g
Initial temperature = 100°C
Final temperature = 22°C
Unknown:
Amount of heat transferred to the water = ?
Solution:
The quantity of heat transferred to the water is a function of mass and temperature of the iron;
H = m c Ф
m is the mass of the iron
Ф is the change in temperature
C is the specific heat capacity of iron = 0.444 J/g°C
Now;
insert the parameters and solve;
H = 200 x 0.444 x (100-22)
H = 6926.4J
Since both hv same mass and elsstic collision, so their velocity will exchange. Bob A will stop and bob B will move with speed of A just before the collision.
Speed will be = squreroot ( 2*g*L)
L is length of pendulum
Answer:
Part c)
Explanation:
Part a)
As per Coulomb's law we know that force on a charge placed in electrostatic field is given as
now acceleration of charge is given as
now if charge moved through the distance D in electric field and its speed changes from vo to fraction f of speed of light c
then we will have
so we have
Part b)
Now using work energy theorem we can say that total work done by electric force on moving charge will convert into kinetic energy
So we will have
so we have
Part c)
Now if an electron is accelerated using this field
then we have
so we have