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3 years ago

What volume of 0.100 m sodium chloride must be added to 75.0 ml of 0.200 m lead(ii) nitrate to precipitate all of the lead ions?

1 answer:

5 0

Reaction for precipitation is
Pb(NO3)2(aq) + 2Nacl(aq)→PbCL2(s)+2NaNO3(aq)
The given reaction is
The mol of Nacl required is =2×mol of Pb(NO3)2 which is present.
∴M(Nacl)×V(Nacl) =2×M(Pb(NO3)2 ×V(Pb(NO3)2
o.100M×V(Nacl)=2×0.200 MX75.0ML
V(Nacl = 300mL.

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Liquid nitrogen has a density of 0.808 g/mL and boils at 77 K. Researchers often purchase liquid nitrogen in insulated 195-L tan

Reika [66]

Answer:

The nswer to the question is

The maximum fraction of the air in the room that could be displaced by the gaseous nitrogen is 0.548 or 54.8 %

Explanation:

To solve the question we note that

The density of the liquid nitrogen = 0.808g/mL and the volume is 195 L tank (vaporised)

Therefore since density = mass/volume we have

mass = Density × volume = 0.808 g/mL × 195 L × 1000 ml/L =157560 g

In gaseous form the liquid nitrogen density =1.15 g/L

That is density = mass/volume and volume = mass/density = 157560 g/(1.15g/L) or

volume = 137008.69565 L

The dimension of the room = 10 m × 10 m × 2.5 m = 250 m³ and

1 m³ is equivalent to 1000 L, therefore 250 m³ = 250 m³ × 1000 L/m³ = 250000L

Therefore fraction of the volume occupied by the gaseous nitrogen =

137008.69565 L/250000 L = 0.548

Therefore the gaseous nitrogen occpies 54.8% of the room

7 0

3 years ago

After isolating the pure crystals on a Hirsch funnel, wash them with solvent, but they dissolve and disappear into the funnel. W

AlladinOne [14]

Answer:

The pure crystals were soluble in the wash solvent.

Explanation:

The pure crystals on the funnel dissolved because they were soluble in the solvent used for washing. They were carried into the filter flask by the solvent.

3 0

3 years ago

Covalent bonding is important between atoms of biological molecules, but other factors are important for self-assembly. For exam

Gekata [30.6K]

Answer:

1. Polar

2 nonpolar

3. Nitrogen or oxygen

4.carbon

5.Repelled by and attracted to

5 0

3 years ago

Why does the reaction proceed more quickly when the surface area is increased?

Gelneren [198K]

When particles collide with the surface of the solid.

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3 years ago

Dalton’s Law CalculationA mixture of H₂, N₂ and Ar gases is present in a steel cylinder. The total pressure within the cylinder

Zolol [24]

Answer:

A) The partial presssure of CO₂ is 167 mm Hg

B) The partial presssure of N₂ is 354 mm Hg

C) The partial presssure of Ar is 235 mm Hg

D) The partial presssure of H₂ is 86 mm Hg

Explanation:

Dalton's law of partial pressures is basically expressed by the following statement:

The total pressure of a mixture is equal to the sum of the partial pressures of its components.

So initially we have:

$P_{T}$ = total presure of the system (675 mm Hg).

$P_{N_2}$ = partial pressure of N₂ (354 mm Hg).

$P_{Ar}$ = partial pressure of Ar (235 mm Hg).

Using Dalton's law we can find the partial pressure of H₂:

$P_{T}=P_{N_2}+P_{Ar}+P_{H_2}$

675 mm Hg=354 mm Hg + 235 mm Hg + $P_{H_2}$

$P_{H_2}$ = 675 mm Hg - 354 mm Hg - 235 mm Hg

$P_{H_2}$ =86 mm Hg

If CO₂ gas is added to the mixture, at constant temperature, and the volume is the same, the difference between the new total pressure and the previous total pressure is equal to the partial pressure of CO₂.

$P_{T}=P_{N_2}+P_{Ar}+P_{H_2}+P_{CO_2}$

842 mm Hg= 354 mm Hg + 235 mm Hg + 86 mm Hg + $P_{CO_2}$

$P_{CO_2}$ = 842 mm Hg - 354 mm Hg - 235 mm Hg - 86 mm Hg

$P_{CO_2}$ = 167 mm Hg

4 0

3 years ago