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3 years ago

If a 1000. ml of linseed oil has a mass of 929 g, what is the density of the oil

1 answer:

5 0

$Formula\ for\ density:\\\\
density=\frac{mass}{volume}\\\\
mass=929g=0,929kg\\\\
volume=1000ml=0,001m^3\\\\
denisty=\frac{0,929kg}{0,001m^3}=
\boxed{929\frac{kg}{m^3}}$

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Structure of 4-ethylheptene

Kisachek [45]

Answer:

PubChem CID 16663

Structure Find Similar Structures

Chemical Safety Laboratory Chemical Safety Summary (LCSS) Datasheet

Molecular Formula C9H20

Synonyms 4-ETHYLHEPTANE 2216-32-2 Heptane, 4-ethyl- 4-ethyl-heptane 4-ethyl heptane

Explanation:

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3 years ago

For the following reaction, 5.04 grams of nitrogen gas are allowed to react with 8.98 grams of oxygen gas: nitrogen(g) + oxygen(

OLga [1]

Answer:

1. 10.8 g of NO

2. N₂ is the limting reagent

3. 3.2 g of O₂ does not react

Explanation:

We determine the reaction: N₂(g) + O₂(g) → 2NO(g)

We need to determine the limiting reactant, but first we need the moles of each:

5.04 g / 29 g/mol = 0.180 moles N₂

8.98 g / 32 g/mol = 0.280 moles O₂

Ratio is 1:1, so the limiting reactant is the N₂. For 0.280 moles of O₂ I need the same amount, but I only have 0.180 moles of N₂

Ratio is 1:2. 1 mol of N₂ can produce 2 moles of NO

Then, 0.180 moles of N₂ may produce (0.180 .2) / 1 = 0.360 moles NO

If we convert them to mass → 0.360 mol . 30 g/1 mol = 10.8 g

As ratio is 1:1, for 0.180 moles of N₂, I need 0.180 moles of O₂.

As I have 0.280 moles of O₂, (0.280 - 0.180 ) = 0.100 moles does not react.

0.1 moles . 32 g/mol = 3.2 g of O₂ remains after the reaction is complete.

8 0

3 years ago

Read 2 more answers

Coal can be used to generate hydrogen gas (a potential fuel) by this endothermic reaction. If this reaction mixture is at equili

VladimirAG [237]

The question ask to predict the effect where as coal can be used to generate hydrogen gas by this endothermic reason and the best answer among your choices based on the element you give is letter C. raising the temperature of the reaction mixture. I hope my answer is correct

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4 years ago

Please answer the chemistry question shown in the attachment photo! 25 points!

iogann1982 [59]

I’m so sorry if it’s wrong but I think it’s this.....

Answer:

2NaHCO3(s) = Na2CO3(s) + CO2(g) + H2O(g).

And I found it on Quora.com
By the way NaHCO3 is Sodium bicarbonate but a.k.a Baking soda
Hoped this helped :)

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3 years ago

How many lead (Pb) atoms will be generated when 5.38 moles of ammonia react according to the following equation: 3PbO+2NH3→3Pb+N

jasenka [17]

Answer:

4.86×10^23 molecule of Pb

Explanation:

Based on that equation, for every 2 moles of ammonia, you get 3 moles of lead.

So:

2 mol NH3/ 3 mol Pb

Using this ratio we can find the amounts of either molecule. Given 5.38 mol NH3:

(5.38 NH3)(3 Pb/ 2 NH3) = (5.38)(3/2) mol Pb = 8.07 mol Pb

Then, we just need to use Avagadro's number to get the number of molecules.

(8.07)(6.02×10^23) = 4.86×10^23 molecule of Pb

4 0

3 years ago

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