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natita [175]
3 years ago
10

If 3.50 L of propane at 24°C and 62.2 kPa is completely burned in excess oxygen, how many moles of carbon dioxide will be produc

ed?

Chemistry
1 answer:
Eva8 [605]3 years ago
4 0
1) convert Celsius to Kelvin
24 + 273 = 297

2) convert kPa to atm
62.2 / 101.3 = 0.614

3) plug numbers into the ideal gas law formula

Answer: 0.088 mols

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<span>Answer is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁<span>).
k</span>₁<span> = 0,000643 1/s.
k</span>₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

1/T₁<span> = 1/622 K = 0,0016 1/K.
1/T</span>₂<span> = 1/666 K = 0,0015 1/K.
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Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

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