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bixtya [17]
3 years ago
13

Assume that the rate law for a generic chemical reaction is rate = [a][b]3 . what is the reaction order in a, the reaction order

in b, and the overall reaction order?
Chemistry
1 answer:
SIZIF [17.4K]3 years ago
8 0
If the reaction is
     X + Y → Products

Then the rate is
     R = k[X]ᵃ [Y]ᵇ

Where,
R = the rate of the reaction (mol L⁻¹ s⁻¹)
k = rate constant
[X] and [Y] = concentrations of the reactants (mol L⁻¹)
a = order of the reaction with respect to X
b = order of the reaction with respect to Y
overall reaction order, n = a + b

according to the given rate expression,
rate = [a][b]³

order of the reaction with respect to 'a' is 1
order of the reaction with respect to 'b' is 3

Overall reaction order = 1 + 3
                                       = 4
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Two perfumes are released at the same time. If one is standing 7.5 m from the point of release. Perfume A (molar mass 275 g/mol)
natta225 [31]
According to Graham's Law of Diffusion," Diffusion of Gas is inversely proportional to square root of its Molecular Mass or Density".

                          rᵇ/rᵃ  =  \sqrt{da/db}
Or,
                          rᵇ/rᵃ  =  \sqrt{Ma/Mb}     ----- (1)
As, 
                          Ma  =  275 g/mol

                          Mb  =  205 g/mol

Putting Values in eq.1,

                          rᵇ/rᵃ  =  \sqrt{275/205}

                          rᵇ/rᵃ  =  1.15

Result:
          Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.
6 0
3 years ago
Write the Lewis structure for the following<br> H20<br> So2
Tasya [4]

See the sketch attached.

<h3>Explanation</h3>

The Lewis structure of a molecule describes

  • the number of bonds it has,
  • the source of electrons in each bond, and
  • the position of any lone pairs of electrons.

Atoms are most stable when they have eight or no electrons in their valence shell (or two, in case of hydrogen.)

  • Each oxygen atom contains six valence electrons. It demands <em>two</em> extra electrons to be chemically stable.
  • Each sulfur atom contains six valence electrons. It demands <em>two </em> extra electrons to be chemically stable.
  • Each hydrogen atom demands <em>one</em> extra electron to be stable.

H₂O contains two hydrogen atoms and one oxygen atom. It would take an extra 2 + 2  × 1 = 4 electrons for all its three atoms are stable. Atoms in an H₂O would achieve that need by sharing electrons. It would form a total of 4 / 2 = 2 O-H bonds.

Each O-H bond contains one electron from oxygen and one from hydrogen. Hydrogen has no electron left. Oxygen has six electrons. Two of them have went to the two O-H bonds. The remaining four become 4 / 2 = 2 lone pairs. The lone pairs repel the O-H bonds. By convention, they are placed on top of the two H atoms.

Similarly, atoms in a SO₂ molecule demands an extra 2 × 2 + 2 = 6 electrons for its three atoms to become chemically stable. It would form 6 / 2 = 3 chemical bonds. Loops are unlikely in molecules without carbon. As a result, one of the two O atoms would form two bonds with the S atom while the other form only one.

Atoms are unstable with an odd number of valence electrons. The S atom in SO₂ would have become unstable if it contribute one electron to each of the three bond. It would end up with 3 × 2 + 3 = 9 valence electrons. One possible solution is that it contributes two electrons in one particular bond. One of the three bonds would be a coordinate covalent bond, with both electrons in that bond from the S atom. In some textbooks this type of bonds are also known as dative bonds.

Dots and crosses denotes the origin of electrons in a bond. Use the same symbol for electrons from the same atom. Electrons from the oxygen atoms O are shown in blue in the sketch. They don't have to be colored.

7 0
3 years ago
A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil
Ludmilka [50]

Answer:

Volume : 1.25 L

Explanation:

We are given here that the volume ( V_1 ) = 1.50 Liters, the initial moles ( held at 25 °C ) = 3.00 mol, and the final moles ( n_2 ) = 3.00 - 0.5 = 2.5 mol. The final mol is calculated given that 0.50 mol of gas are released from the prior 3.00 moles of gas.

Volume ( V_1 ) = 1.50 L,

Initial moles ( n_1 ) = 3.00 mol,

Final Volume ( n_2 ) = 3.00 - 0.5 = 2.5 mol

Applying the combined gas law, we can calculate the final volume ( V_2 ).

P_1V_1 / n_1T_1 = P_2V_2 / n_2T_2 - we know that the pressure and temperature are constant, and therefore we can apply the following formula,

V_1 / n_1 = V_2 / n_2 - isolate V_2,

V_2 = V_1 n_2 / n_1 = 1.50 L * 2.5 mol / 3.00 mol = ( 1.5 * 2.5 / 3 ) L = 1.25 L

The volume of the balloon will be 1.25 L.

6 0
3 years ago
In which circumstance is displacement the same as distance traveled?
Ede4ka [16]
Distance travelled will be equal to displacement when the line drawn is completely straight. 

Hopefully, this helps.
8 0
3 years ago
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Draw the Lewis dot structure for benzene
gavmur [86]

Answer:

Explanation:

Benzene is an example for six membered aromatic hydrocarbons

8 0
3 years ago
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