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melisa1 [442]
2 years ago
13

John attached a ball to a spring

Physics
1 answer:
chubhunter [2.5K]2 years ago
8 0

Answer:

C down

Explanation:

The ball is pulling the spring down so this must be the direction of the force

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A ball of silly putty hits andsticks to a bowling ball that was initially at rest. After thecollision, the total kinetic energy
Jobisdone [24]

Answer:

3. less than the kinetic energy of thesilly putty before the collision.

Explanation:

This is because kinetic energy is dependent on the mass and velocity of an object. Mathematically, it is given as:

K. E. = ½*m*v²

Where m = mass

v = velocity

In the case of the silly putty, we know that the masses of the ball of silly putty and the bowling ball are conserved, hence, the kinetic energy depends solely on the velocity at which the object moves.

After the collision with the bowling ball, because of how heavy a bowling ball is, the speed of the silly putty and bowling ball will definitely be less than the speed of the silly putty before collision, i. e. u > v.

Hence, the kinetic energy after collision will be less than the kinetic energy before collision.

7 0
3 years ago
. If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular
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7 0
2 years ago
Oakwood Community College Registration
Natasha2012 [34]

Answer:

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6 0
3 years ago
Derive a relation between Universal Gravitational Constant (G) and Acceleration due to gravity(g)?
snow_tiger [21]
Suppose earth is a soid sphere which will attract the body towards its centre.So, acc. to law of gravitation force on the body will be,
F=G*m1m2/R^2
but we now that F=ma
and here accleration(a)=accleration due to gravity(g),so
force applied by earth on will also be mg
replace above F in formula by mg and solve,
F=G*mE*m/R^2                             ( here mE is mass of earth and m is mass of body)
mg=G*mEm/R^2
so,
g =G*mE/R^2




4 0
3 years ago
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AlladinOne [14]
Uniformly around the globe. it is mostly found in earths atmosphere. 
5 0
3 years ago
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