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Alona [7]
3 years ago
10

Cuanto pesan 2 moles de HCI

Chemistry
1 answer:
maks197457 [2]3 years ago
5 0

Answer:

FORMULA: HCl PESO MOLECULAR: 36.46 g/mol COMPOSICION: Cl: 97.23 % y H: 2.76 %. GENERALIDADES: El ácido clorhídrico es una disolución acuosa de cloruro de hidrógeno.

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Which of the following molecules would you expect to have a dipole moment of zero?
Mashcka [7]

Answer:

CCl2=CCl2

Explanation:

Recall that the individual dipole moments in a symmetrical molecule cancel out each other thereby making the overall molecule to be non polar.

CCl2=CCl2 contain individual polar bonds but the molecule is highly symmetrical thus its dipole cancel out and the molecule has no overall dipole moment, hence CCl2=CCl2 has a dipole moment of zero .

6 0
3 years ago
At standard ambient temperature and pressure (SATP), a gas has density of 1.5328g/L. What is the molar mass of the gas?
ahrayia [7]

The standard ambient temperature and pressure are

Temperature =298 K

Pressure = 1atm

The density of gas is 1.5328 g/L

density = mass of gas per unit volume

the ideal gas equation is

PV = nRT

P = pressure = 1 atm

V = volume

n = moles

R= gas constant = 0.0821 Latm/mol K

T = 298 K

moles = mass / molar mass

so we can write

n/V = density / molar mass

Putting values

Pressure=\frac{nRT}{V}=\frac{massXRT}{VXmolarmass}

Pressure=\frac{densityXRT}{molarmass}

molarmass=\frac{densityXRT}{Pressure}=\frac{1.5328X0.0821X298}{1}=37.50

Thus molar mass of gas is 37.50g/mol

6 0
4 years ago
56. The electron configuration for phosphorous is [Ar]3s23p4.<br> a. TRUE<br> b. FALSE
melomori [17]

Answer:

False

Explanation:

7 0
2 years ago
Read 2 more answers
It is a vocal music of Mindoro​
Anna [14]

Answer:

instrumental music is used in festivals, rituals, etc.

Explanation:

8 0
3 years ago
What is the molarity of a solution made by dissolving 10.305 g of calcium carbonate, CaCO3, in water and diluting with water to
Gemiola [76]

Answer:

0.9359 M

Explanation:

M(CaCO3)=100.1 g/mol

10.305 g * 1 mol/100.1 g = 10.305/100.1 mol CaCO3

(10.305/100.1 mol )/0.1100 L = 0.936 mol/L = 0.9359 M

8 0
3 years ago
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