All categories

4 years ago

Which of these does an ideal pendulum experience? Check all that apply.

Physics

2 answers:

tamaranim1 [39]4 years ago

8 0

For ideal pendulum we will say

The string in that case must be massless and in-extensible

Frictional forces must be zero

there should not be any contact surface of pendulum

Whole mass of pendulum must be concentrated at the center

so above all conditions of pendulum we will say time period is given as

$T = 2\pi \sqrt{\frac{L}{g}}$

now the correct answer will be

gravitational force

tension

inertia

Naddika [18.5K]4 years ago

3 0

Gravitational, tension and inertia have the ideal pendulum experience.

Answer: Option B,E,F

Explanation:

Ideal pendulum is an object or ball suspended by a thread which will freely vibrate from left to ring and then from right to left and this process repeats continuously.

The rod is suspended by a thread which represents tension, since it is always confined within its region, it is due to inertia, and gravity is the main force acting on all objects in the earth.

You might be interested in

what is the rotational kinetic energy of the earth? use the moment of inertia you calculated in part a rather than the actual mo

Ivenika [448]

The Earth's rotational kinetic energy is the kinetic Energy that the Earth

has due to rotation.

The rotational kinetic energy of the Earth is approximately 3.331 × 10³⁶ J

Reasons:

The parameters required for the question are;

Mass of the Earth, M = 5.97 × 10²⁴ kg

Radius of the Earth, R = 6.38 × 10⁶ m

The rotational period of the Earth, T = 24.0 hrs.

$The \ moment \ of \ inertia \ of \ uniform \ sphere \ is \ I = \mathbf{\dfrac{2}{5} \cdot M \cdot R^2}$

Which gives;

$\mathbf{I_{Earth}} = \dfrac{2}{5} \times 5.97 \times 10 ^{24} \cdot \left(6.38 \times 10^6 \right)^2 = 9.7202107 \times 10^{37}$

$\mathrm{The \ rotational \ kinetic \ energy \ is} \ E_{rotational} = \mathbf{\dfrac{1}{2} \cdot I \cdot \omega^2}$

$\mathrm{The \ angular \ speed, \ \omega} = \mathbf{\dfrac{2 \dcdot \pi}{T}}$

Therefore;

$\omega = \dfrac{2 \cdot \pi}{24} = \dfrac{\pi}{24}$

Which gives;

$\mathbf{E_{rotational}} = \dfrac{1}{2} \times 9.7202107 \times 10^{37} \times \left( \dfrac{\pi}{12} \right)^2 = 3.331 \times 10^{36}$

The rotational kinetic energy of the Earth, $E_{rotational}$ = 3.331 × 10³⁶ Joules

Learn more here:

brainly.com/question/13623190

The moment of inertia from part A of the question (obtained online) is that of the Earth approximated to a perfect sphere.

Mass of the Earth, M = 5.97 × 10²⁴ kg

Radius of the Earth, R = 6.38 × 10⁶ m

The rotational period of the Earth, T = 24.0 hrs

3 0

3 years ago

one of the ways, covered in the article and in class, that we charged an object was rubbing it against carpet on the floor true

astraxan [27]

Answer:

It is possible to statically charge objects by rubbing it against carpet fibers, but I'm not sure if that was in the article that you read.

Explanation:

Static charge can build up via carpet fibers.

5 0

3 years ago

I think these two are simple questions.. but I need help asap..... TT

frosja888 [35]

1) The average velocity is 56 m/min

2) The average velocity is -83 m/min

Explanation:

The average velocity of an object is given by

$v=\frac{d}{t}$

where

d is the displacement (change in position)

t is the time elapsed

In the graph in the problem, the displacement corresponds to the distance, therefore to the change in the y-variable ( $\Delta y$ ), while the time elapsed is the change in the x-variable ( $\Delta x$ ), so the average velocity can be written as