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Strike441 [17]
3 years ago
7

N2 (g) + 3H2 (g) -->2 NH3 (g) The equation above is the equation for the Haber process. In a certain reaction, you start with

6.0 moles of nitrogen and 10.0 moles of hydrogen. How many moles of ammonia will be produced in the reaction?
Chemistry
1 answer:
Kazeer [188]3 years ago
6 0
For ever 1 mole of nitrogen you need 3 moles of hydrogen to make 2 moles of Ammonia.
We only have 10 moles of hydrogen so that is the limiting as there is more nitrogen then hydrogen in this particular case.
Therfore the ratio is 2 ammonia to 3 hydrogen [2:3]
Do 2/3which is 0.6667. This is how many moles of ammonia you get per mole of hydrogen.
Multiply that by 10 and you get 6.67 moles of Ammonia produced [3 significant figures]

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