Answer:
There are following type of hydraulic cylinders
1.Single acting
2.Double acting
3.Single acting spring loaded
4.Non differential type
5.Ram type
6.Piston type
7.Actuating type
8.Telescopic type
Answer:
1 ) Accuracy of the Machine Tool
2) Load bearing capacity
3) Linearity in the product line
4) Torque of the machine
Explanation:
we know that machine tool is the permanent essential in manufacturing industries
it is a machine use for different form like cutting , grinding and boring etc
so 1st is
1 ) Accuracy of the Machine Tool
we know it is very important Characteristic of the machine tool because when we use it in manufacturing unit Accuracy of the Machine Tool should be higher concern
2) Load bearing capacity
we should very careful about Load bearing capacity because how much amount of load tool will bear check by some parameter like creep , shear stress and strength etc
3) Linearity in the product line
Linearity in the product line mean that it should be group of related product produced by the any one of the manufacturer otherwise it will take time or it may be intermixing
4) Torque of the machine
we know that Torque is a rotational force or a turning force so amount of force multiplied by the distance of the operation
and we know torque per second give the power rating of machine tool
Answer:
Change in length = 0.1257 mm
Change in diameter= -0.03771mm
Explanation:
Given
Diameter, d = 15 mm
Length of rod, L = 200mm
F = Force= 300N
d = 0.015m
Ep=2.70 GPa, np=0.4.
First, we have to calculate the normal stress using
σ = F/A where F = Force acting on the Cross-sectional area
A = Area
Area is calculated as πd²/4 where d = 0.015m
A = 22/7 * 0.015²/4
A = 0.000176785714285m²
A = 1.768E-4m²
So, stress. σ = 300N/1.768E-4m²
σ = 1696832.579185520Pa
σ = 1.697MPa
Calculating E(long)
E(long) = σ /Ep
E(long) = 1.697E-3/2.70
E(long) = 0.0006285
At this point, we fan now calculate the change in length of the element;
∆L = E(long) * L
∆L = 0.0006285 * 200mm
∆L = 0.1257mm
Calculating E(lat)
E(lat) = -np * E(long)
E(lat) = -4 * 0.0006285
E(lat) = -0.002514
At this point, we can now calculate the change in diameter of the element;
∆D = E(lat) * D
∆L = -0.002514 * 15mm
∆L = -0.03771mm
Engineer technicians typically hold a two-year associates degree, while engineering technologists likewise hold a bachelors degree.
