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notsponge [240]

3 years ago

11

Hydrogen peroxide, H2O2, enters a gas generator at 25 Celsius, 500 kPa, at the rate of 0.1 kg/s and is decomposed to steam and o

xygen exiting at 800 K, 500 kPa. The resulting mixture is expanded through a turbine to atmospheric pressure, 100 kPa. Determine the power output of the turbine and the heat transfer rate in the gas generator. The enthalpy of formation of liquid H2O2 is −187 583 kJ/kmol.

1 answer:

Blizzard [7]3 years ago

8 0

Take a look at the pictures that should help you out.

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The news media often report an earthquake's magnitude on the Richter scale. Which of the following items are characteristics of

vlabodo [156]

The correct answers are A) determined from the amplitude recorded by a single seismometer. C) represents the amount of energy released. D) uses a logarithmic scale.

The news media often report an earthquake's magnitude on the Richter scale. The following items are characteristics of a Richter earthquake magnitude: determined from the amplitude recorded by a single seismometer, represents the amount of energy released, and uses a logarithmic scale.

When measuring the scale of the magnitude of earthquakes, the Richter scale measures the scale od moderated size earthquakes. It was invented by two United States seismologists: Charles F. Richer and Beno Gutenberg. They developed the measure in California when they were researching from 1927 through 1936, in the Seismological Laboratory of the Carnegie Institution of Washington, in Pasadena, California.

8 0

3 years ago

You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the rea

vovangra [49]

Answer: 33.35 minutes

Explanation:

A(t) = A(o) *(.5)^[t/(t1/2)]....equ1

Where

A(t) = geiger count after time t = 100

A(o) = initial geiger count = 400

(t1/2) = the half life of decay

t = time between geiger count = 66.7 minutes

Sub into equ 1

100=400(.5)^[66.7/(t1/2)

Equ becomes

.25= (.5)^[66.7/(t1/2)]

Take log of both sides

Log 0.25 = [66.7/(t1/2)] * log 0.5

66.7/(t1/2) = 2

(t1/2) = (66.7/2 ) = 33.35 minutes

3 0

3 years ago

Your new team is working hard, but they are all less experienced than you and don't complete their tasks as quickly.What would y

irina1246 [14]

I believe most likely: (C) least likely: (B)

8 0

3 years ago

Refrigerant-134a enters the expansion valve of a refrigeration system at 120 psia as a saturated liquid and leaves at 20 psia. D

Shkiper50 [21]

Solution :

$P_1 = 120 \ psia$

$P_2 = 20 \ psia$

Using the data table for refrigerant-134a at P = 120 psia

$h_1=h_f=40.8365 \ Btu/lbm$

$u_1=u_f=40.5485 \ Btu/lbm$

$T_{sat}=87.745^\circ F$

∴ $h_2=h_1=40.8365 \ Btu/lbm$

For pressure, P = 20 psia

$h_{2f} = 11.445 \ Btu/lbm$

$h_{2g} = 102.73 \ Btu/lbm$

$u_{2f} = 11.401 \ Btu/lbm$

$u_{2g} = 94.3 \ Btu/lbm$

$T_2=T_{sat}=-2.43^\circ F$

Change in temperature, $\Delta T = T_2-T_1$

$\Delta T = -2.43-87.745$

$\Delta T=-90.175^\circ F$

Now we find the quality,

$h_2=h_f+x_2(h_g-h_f)$

$40.8365=11.445+x_2(91.282)$

$x_2=0.32198$

The final energy,

$u_2=u_f+x_2.u_{fg}$

$=11.401+0.32198(82.898)$

$=38.09297 \ Btu/lbm$

Change in internal energy

$\Delta u= u_2-u_1$

= 38.09297-40.5485

= -2.4556

5 0

2 years ago

Prefix version of 6600 volts

GenaCL600 [577]

Answer:

6.6 kilo volts = 6.6 k volts

Explanation:

A prefix is a word, number or a letter that is added before another word. In physics we have different prefixes for the exponential powers of 10, that are placed before units in place of those powers. Some examples are:

deci (d) ------ 10⁻¹

centi (c) ------ 10⁻²

milli (m) ------ 10⁻³

kilo (k) ------ 10³

mega (M) ----- 10⁶

giga (G) ------ 10⁹

We have:

6600 volts

converting to exponential form:

=> 6.6 x 10³ volts

Thus, we know that the prefix of kilo (k) is used for 10³.

Hence,

=> <u>6.6 kilo volts = 6.6 k volts</u>

7 0

3 years ago